Let
Eqn 1 be <span>8x = 2y + 5
</span><span>
And,
</span><span>3x = y + 7
</span>therefore
Eqn 2 is <span> x= 1/3(y+7)
</span>
Sub 2 into 1 gives:
8(1/3(y+7)) = 2y + 5
8/3(y) + 56/3 = 2y + 5
2/3(y) = –41/3
2y=–41
y= –41/2
X= –9/2.
Therefore, <span>{(-9/2, -41/2)} is your solution set. As the notation is equal to (x,y)</span>
Answer:
x=36 degrees
Step-by-step explanation:
Remember that all angles of a triangle must add up to 180 degrees due to the Angle Addition Postulate. So let's plug it in! x+65+79=180
Now you solve, x=180-79-65
x=36!
x=36 degrees
2x+y = -5. Solve this for y. We get y = -2x - 5. Find y^2: 4x^2 + 20x + 25. Substitute 4x^2 + 20x + 25 for y^2 in the first equation:
x^2 + 4x^2 + 20x + 25 = 25
Then 5x^2 + 20x = 0, so that x = 0. Subst. 0 for x in the 2nd eqn and find the value of y. Write your solutions as shown above: ( , ) and ( , ).
