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3 years ago

How does a drupe fruit differ from a hesperidum fruit.

Chemistry

2 answers:

pshichka [43]3 years ago

4 0

Answer:

Fleshy Fruits: All of most of the ovary wall (pericarp) is soft or fleshy at maturity. ... partitions, juicy seed vesicles, and a leathery exocarp similar to a hesperidium. ... This is a very common dry fruit found in many different plant families.

Explanation:

Nadusha1986 [10]3 years ago

3 0

Answer:

Explanation:

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Calculate the volume in milliliters of a 0.420mol / L barlum chlorate solution that contains 25.0 g of barium chlorate (Ba(ClO 3

Pachacha [2.7K]

Answer: The volume of barium chlorate is 195.65 mL

Explanation:

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of barium chlorate = 25.0 g

Molar mass of barium chlorate = 304.23 g/mol

Molarity of solution = 0.420 mol/L

Volume of solution = ?

Putting values in above equation, we get:

$0.420mol/L=\frac{25.0\times 1000}{304.23\times V}\\\\V=\frac{25.0\times 1000}{304.23\times 0.420}=195.65mL$

Hence, the volume of barium chlorate is 195.65 mL

6 0

3 years ago

DUPLICATE

Svet_ta [14]

As in relative abundance , one is take reference
So,
One is taken as 1:
Other is subtracted from it:
(1 - 0.6011)(atomic mass of Ga-71)

Equation can be written as:
69.723 = (0.6011)(68.9256) + (1-0.6011)x 
(1-0.6011) is the percentage abundance of Ga-71 expressed in percentage: 

Solving for x 
28.2918 = 0.3989 x 
x= 70.9246.......

7 0

3 years ago

Determine the volume (in liters) of a 87.8-9 sample of OF2 gas at 307 torr and 264°C.

expeople1 [14]

Answer:

V = 177.4 L.

Explanation:

Hello there!

In this case, since this gas can be assumed as ideal due to the given data, we can use the following equation:

$PV=nRT\\\\PV=\frac{m}{MM}RT$

Thus, by solving for volume we obtain:

$V=\frac{mRT}{MM*P}$

So we can plug in the temperature in Kelvins (537 K), the pressure in atmospheres (0.404 atm) and the molar mass (54 g/mol) to obtain:

$V=\frac{87.8g*0.08206\frac{atm*L}{mol*K}*537K}{54g/mol*0.404atm}\\\\V=177.4L$

Best regards!

6 0

3 years ago

The pressure inside your

VMariaS [17]

Answer: The pressure 12.2 psi is expressed in millimeters of mercury (mm Hg) as 630.9221 mm Hg.

Explanation:

Given: Pressure = 12.2 psi

According to the standard conversion of units, 14.7 psi = 1 atm = 760mmHg.

Therefore, 1 psi equal to how many mm Hg is calculated as follows.

$14.7 psi = 760 mm Hg\\1 psi = \frac{760}{14.7} mm Hg\\= 51.7149 mm Hg$

Hence, 12.2 psi will be converted into mm Hg as follows.

$1 psi = 51.7149 mm Hg\\12.2 psi = 12.2 psi \times \frac{51.7149 mm Hg}{1 psi}\\= 630.9221 mm Hg$

Thus, we can conclude that the pressure 12.2 psi is expressed in millimeters of mercury (mm Hg) as 630.9221 mm Hg.

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3 years ago

Calculate the volume in liters of a barium acetate solution that contains of barium acetate . Be sure your answer has the correc

Ilya [14]

Answer:

1.09 L

Explanation:

There is some info missing. I think this is the original question.

Calculate the volume in liters of a 0.360 mol/L barium acetate solution that contains 100 g of barium acetate. Be sure your answer has the correct number of significant digits.

The molar mass of barium acetate is 255.43 g/mol. The moles corresponding to 100 grams are:

100 g × (1 mol/255.43 g) = 0.391 mol

0.391 moles of barium acetate are contained in an unknown volume of a 0.360 mol/L barium acetate solution. The volume is:

0.391 mol × (1 L/0.360 mol) = 1.09 L

5 0

4 years ago

Read 2 more answers

How does a drupe fruit differ from a hesperidum fruit. ​

How does a drupe fruit differ from a hesperidum fruit.