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noname [10]
3 years ago
9

for 2Na (s) +Cl2(g)->2NaCl(s) how many grams of sodium chloride will be made from 115 g of sodium metal when when reacted wit

h excess chlorine gas
Chemistry
1 answer:
alexandr1967 [171]3 years ago
5 0

 The grams  of sodium   chloride that will be made is 292.5 g


<u><em>calculation</em></u>

2Na  +Cl₂ → 2NaCl

step 1: calculate the  moles of Na

moles  =   mass/molar mass

From periodic table the  molar mass  of Na = 23 g/mol

moles = 115 g/23 g /mol =  5  moles

Step 2 : use the mole ratio to determine the  moles of NaCl

Na:NaCl   is  2:2 = 1:1  therefore the moles of NaCl  is also= 5 moles


Step  3: find the mass of NaCl

mass= moles  x molar mass

The  molar mass of NaCl = 23 + 35 .5 =58.5 g/mol

mass= 5 moles x 58.5 g/mol =292.5  g




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Barium sulfate is made by the following reaction.
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                      %age Yield =   96 %

Explanation:

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                      Ba(NO₃)₂ + Na₂SO₄ → BaSO₄ + 2 NaNO₃

Step 1: <u>Calculate moles of Ba(NO₃)₂:</u>

Moles  =  Mass / M.Mass

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Step 2: <u>Find out moles of BaSO₄ formed:</u>

According to balance chemical equation,

                  1 mole of Ba(NO₃)₂ produced  =  1 mole of BaSO₄

So,

        0.2873 moles of Ba(NO₃)₂ will produce  =  X moles of BaSO₄

Solving for X,

                      X =  0.2873 mol × 1 mol / 1 mol

                       X =  0.2873 moles of BaSO₄

Step 3: Calculate Theoretical Mass of BaSO₄:

Mass  =  Moles × M.Mass

Mass  =  0.2873 mol × 233.38 g/mol

Mass  = 67.07 g of BaSO₄

Step 4: <u>Calculate %age Yield as:</u>

                 Theoretical Yield  =  67.07 g

                  Actual Yield  =  64.4 g

                  %age Yield  =  <u>???</u>

Formula Used:

                   %age Yield  =  (Actual Yield ÷ Theoretical Yield) × 100

Putting Values,

                   %age Yield  =  (64.4 g ÷ 67.07 g) × 100

                   %age Yield =  96.01 % ≈ 96 %

6 0
2 years ago
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Explanation:

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<h3>Therefore, the ΔG° = -212.3kJ/mol</h3>
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