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irina1246 [14]
3 years ago
12

A loose, icy body with a long, narrow orbit is?

Chemistry
2 answers:
Oxana [17]3 years ago
5 0

Answer:

The correct answer is "a comet".

Explanation:

A loose, icy body with a long, narrow orbit is a comet. A comet is made of ice, that is the reason why most comets start to release their gasses in a process known as outgassing when they pass close to the Sun. Comets have a long, narrow orbit that most of time follows an elliptical path respect to the Sun, which allows that most of the comets do not get close to the Earth.

Firdavs [7]3 years ago
3 0
A loose, icy body with a long, narrow orbit is a comet
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How many grams of Mg(ClO3)2 are needed to make 1,500 mL of a 2.5 N solution ?​
yarga [219]

Answer:

33

Explanation:

3 0
2 years ago
The specific heat of a certain type of cooking oil is 1.75 J/(g⋅°C). How much heat energy is needed to raise the temperature of
Mademuasel [1]

Answer:

\large \boxed{\textbf{609 kJ}}  

Explanation:

The formula for the heat absorbed is

q = mCΔT

Data:

m = 2.07 kg

T₁ = 23 °C

T₂ = 191 °C

C = 1.75 J·°C⁻¹g⁻¹

Calculations:

1. Convert kilograms to grams

2.07 kg = 2070 g

2. Calculate ΔT

ΔT = T₂ - T₁ = 191 - 23  = 168 °C

3. Calculate q

q = \text{2070 g} \times 1.75 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$} \times 168 \,^{\circ}\text{C} = \text{609 000 J} = \textbf{609 kJ}\\\text{The heat energy required is }\large \boxed{\textbf{609 kJ}}

4 0
3 years ago
What are the coefficients that will balance the skeleton equation below?
Vesna [10]

Answer:

the answer is 1,3,2

Explanation:

Balance equation

5 0
3 years ago
What volume of 6.58M HCI is needed to make 500. mL of 3.00M HCI?
zmey [24]

Answer:

228 mL

Explanation:

M1*V1 = M2*V2

M1 = 6.58 M

V1 = ?

M2 = 3.00 M

V2 = 500 mL

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3 0
3 years ago
How many grams of KCN are in 10.0 ml of a 0.10 M solution?
attashe74 [19]

Explanation:

As it is known that molarity is the number of moles present in a liter of solution.

Mathematically,       Molarity = \frac{no. of moles}{Volume in liter}

As it is given that molarity is 0.10 M and volume is 10.0 ml. As 1 ml equals 0.001 L. Therefore, 10.0 ml will also be equal to 0.01 L.

Hence, putting these values into the above formula as follows.

                  Molarity = \frac{no. of moles}{Volume in liter}

                  0.10 M = \frac{no. of moles}{0.01 L}

                        no. of moles = 0.001 mol

As molar mass of KCN is equal to 65.12 g/mol. Therefore, calculate the mass of KCN as follows.

                 No. of moles = \frac{mass}{molar mass}

                                 0.001 mol = \frac{mass}{65.12 g/mol}

                                 mass = 0.06152 g

Thus, we can conclude that 0.06152 grams of KCN are in 10.0 ml of a 0.10 M solution.

3 0
3 years ago
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