Answer:
The estimated impact of the experiment of offering test preparation classes is:
= 8 scores (in performance improvement).
Step-by-step explanation:
Average standardized-test score for the first 10 high schools = 69
Average standardized-test score for the second 10 high schools = 70
After 6 months:
Average standardized-test score for the first 10 high schools offered test preparation classes = 78
The change in the average standardized-test score for the first 10 high schools = 9 (78 - 69)
Average standardized-test score for the second 10 high schools not offered test preparation classes = 71
The change in the average standardized-test score for the second 10 high schools not offered the prep = 1 (71 - 70)
The estimated impact of the experiment of offering test preparation classes is:
= 9 - 1
= 8.
This is easy. All we have to do is 0.2 minus 0.02 which is 0.18 This is because the 2 next to the 2 in the hundredths place is a 2 in the tenths place. I hope this helps!
Do the problem little by little:
First, -20/48 reduces to -5/12.
Next, (t^5) / (t^7) simplifies to 1 / (t^2).
Same with u^2 / u^4: 1 / u^2
v^3 / v^1 = v^2
Let's put the factors back together:
-5 * v^2
--------------------------
12 * u^2 * t^2
-5 v
This could be left as is, or shortened: ----- * [ ------- ]^2
12 t*u
Answer:
0.25
Step-by-step explanation:
1 divided by 4
B is the Answer because that’s the only answer I got with doing the math and it was B