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mezya [45]
2 years ago
8

What happened to the U.S. dollar when President Nixon closed the gold window?

Mathematics
1 answer:
Sav [38]2 years ago
8 0
He announced that the US would no longer convert dollars to gold at fixed value
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The sum of twice a number and 2 is greater than 4
laila [671]

Let's make the inequality.

The sum of twice a number and 2. We're adding and multiply. X will be the number. 2x+2

Is greater than 4. We'll be using the greater than sign. >4; let's put it together.

2x+2>4; let's solve. First by subtracting two on both sides. 2x>2; let's divide by 2. x>1

So, the inequality is 2x+2>4. To solve it, it is x>1.

5 0
3 years ago
Read 2 more answers
Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming poo
kolezko [41]

Let <em>x</em> and <em>y</em> be the unit rates at which one large pump and one small pump works, respectively.

Two large/one small operate at a unit rate of

(1 pool)/(4 hours) = 0.25 pool/hour

so that

2<em>x</em> + <em>y</em> = 0.25

One large/three small operate at the same rate,

(1 pool)/(4 hours) = 0.25 pool/hour

<em>x</em> + 3<em>y</em> = 0.25

Solve for <em>x</em> and <em>y</em>. We have

<em>y</em> = 0.25 - 2<em>x</em>   ==>   <em>x</em> + 3 (0.25 - 2<em>x</em>) = 0.25

==>   <em>x</em> + 0.75 - 6<em>x</em> = 0.25

==>   5<em>x</em> = 0.5

==>   <em>x</em> = 0.1

==>   <em>y</em> = 0.25 - 2 (0.1) = 0.25 - 0.2 = 0.05

In other words, one large pump alone can fill a 1/10 of a pool in one hour, while one small pump alone can fill 1/20 of a pool in one hour.

Now, if you have four each of the large and small pumps, they will work at a rate of

4<em>x</em> + 4<em>y</em> = 4 (0.1) + 4 (0.05) = 0.6

meaning they can fill 3/5 of a pool in one hour. If it takes time <em>t</em> to fill one pool, we have

(3/5 pool/hour) (<em>t</em> hours) = 1 pool

==>   <em>t</em> = (1 pool) / (3/5 pool/hour) = 5/3 hours

So it would take 5/3 hours, or 100 minutes, for this arrangement of pumps to fill one pool.

6 0
3 years ago
Given the vector (4|3) and the transformation matrix (0|1|-1|0), which vector is the imagine after applying the transformation t
horrorfan [7]

Answer:

C.(3|-4)

Step-by-step explanation:

Given the vector:

\left[\begin{array}{ccc}4\\3\end{array}\right]

The transformation Matrix is:

\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]

The image of the vector after applying the transformation will be:

\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4\\3\end{array}\right]\\\\=\left[\begin{array}{ccc}0*4+1*3\\-1*4+0*3\end{array}\right]\\\\=\left[\begin{array}{ccc}3\\-4\end{array}\right]

The correct option is C

7 0
3 years ago
Two number cubes are rolled. What is the probability of rolling a sum of 9 or a sum that is even?
Murljashka [212]

Well I don't know !
Let's figure it out together.

Each cube can land in 6 different ways, so the total number
of possible results with two cubes is (6 x 6) = 36 .

Now we need to figure out how many of those 36 possibilities
meet your specifications ... either 9 or any even number.

Ways to make 9 :

3 . . . 6
6 . . . 3
4 . . . 5
5 . . . 4

Four ways to make 9.
____________________________

Ways to make an even number:

1 . . . 1
3 . . . 1
1 . . . 3
2 . . . 2
5 . . . 1
1 . . . 5
6 . . . 2
2 . . . 6
6 . . . 4
4 . . . 6
6 . . . 6

Eleven ways to make an even number.
_____________________

Total number of ways to succeed = (4 + 11) = 15 ways

So the probability of succeeding (rolling 9 or an even number)
is

               15 / 36  =  5 / 12  =  0.41666... =  (41 and 2/3) % .

8 0
3 years ago
Read 2 more answers
Sum of 2 numbers is 5 difference of the same 2 numbers is 9
liq [111]

Answer:

5 and 4

Step-by-step explanation:

7 0
3 years ago
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