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2 years ago

What is the value of x in the equation -5/4x=-160

Mathematics

2 answers:

Vikentia [17]2 years ago

7 0

Step-by-step explanation:

-5/4x=-160

5/4x=160

x=160×4/5

x=640/5

x=128

Ierofanga [76]2 years ago

4 0

$\\ \sf \longmapsto \: - \frac{ 5}{4} x = - 160 \\ \\ \sf \longmapsto \: \frac{5}{4} x = 160 \\ \\ \sf \longmapsto \: x = 160 \times \frac{4}{5} \\ \\ \sf \longmapsto \: x = 32 \times 4 \\ \\ \sf \longmapsto \: x = 128$

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2 years ago

Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear

AlladinOne [14]

Answer:

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Step-by-step explanation:

we know that

If the three points are collinear

then

$m_A_B=m_A_C$

we have

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The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

step 1

Find the slope AB

we have

$A(1,\frac{2}{3}),B(x,-\frac{4}{5})$

substitute in the formula

$m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}$

$m_A_B=\frac{\frac{-12-10}{15}}{x-1}$

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step 2

Find the slope AC

we have

$A(1,\frac{2}{3}),C(-\frac{1}{2},4)$

substitute in the formula

$m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}$

$m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}$

$m_A_C=-\frac{20}{9}$

step 3

Equate the slopes

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solve for x

$15(x-1)20=22(9)$

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$300x=198+300$

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$x=\frac{498}{300}$

simplify

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