What is the value of x in the equation -5/4x=-160
2 answers:
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Let r = (t,t^2,t^3)
Then r' = (1, 2t, 3t^2)
General Line integral is:
The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector
Fortunately, this simplifies nicely with a 'u' substitution.
Let u = 1+4t^2 +9t^4
du = 8t + 36t^3 dt
After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
Then r' = (1, 2t, 3t^2)
General Line integral is:
The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector
Fortunately, this simplifies nicely with a 'u' substitution.
Let u = 1+4t^2 +9t^4
du = 8t + 36t^3 dt
After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
Answer:
C. Both x is a function of y and y is a function of x
Step-by-step explanation:
A <u>function</u> is a relationship which assigns to each input (from the domain) value, a unique output (from the range).
y is a function of x means x is from domain, y is from range
x is a function of y means y is from domain, x is from range
1. Given
y is a function of x because for each x there is exactly one y corresponding to this x.
2. Rewrite expressing x in terms of y:
x is a function of y because for each y there is exactly one x corresponding to this x.