The answer I came up with was 2.1
Answer:
a. 9.48
b. 195.3
Step-by-step explanation:
convert the corresponding per cent into a decimal (you can move the decimal place to the left by 2 or divide by 100) then just multiply it with the "of" number
Answer:
48 square unit
Step-by-step explanation:
For a rectangle, area is given by
A=bh
Where b is base and h is height as shown in the attached diagram
For a triangle, area is given by
A∆=½bh
Given that ½bh=48
Then bh=2*48=96 square units
The overall area is 96 square units.
The area for 1&2 combined will be given by deducting the area of triangle from the overall area
Area is 96-48=48 square units
Answer:
Integration of I=
=![[\frac{logx}{n+1} x^{(n+1)}]-[\frac{1}{(n+1)^{2}}x^{(n+1)}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Blogx%7D%7Bn%2B1%7D%20x%5E%7B%28n%2B1%29%7D%5D-%5B%5Cfrac%7B1%7D%7B%28n%2B1%29%5E%7B2%7D%7Dx%5E%7B%28n%2B1%29%7D%5D)
Step-by-step explanation:
Given integral is I= 
Take logx=t





I= 
I= 
Using integration by part,
![I= (t)\int [e^{(n+1)t}]\, dt-\int[\frac{d}{dt}{t}\times\int (e^{(n+1)t})]\\\\I= (t) [\frac{1}{n+1}e^{(n+1)t}]-\int[1\times\frac{1}{n+1}e^{(n+1)t}]\,dt\\\\I=[\frac{t}{n+1}e^{(n+1)t}]-[\frac{1}{(n+1)^{2}}e^{(n+1)t}]](https://tex.z-dn.net/?f=I%3D%20%28t%29%5Cint%20%5Be%5E%7B%28n%2B1%29t%7D%5D%5C%2C%20dt-%5Cint%5B%5Cfrac%7Bd%7D%7Bdt%7D%7Bt%7D%5Ctimes%5Cint%20%28e%5E%7B%28n%2B1%29t%7D%29%5D%5C%5C%5C%5CI%3D%20%28t%29%20%5B%5Cfrac%7B1%7D%7Bn%2B1%7De%5E%7B%28n%2B1%29t%7D%5D-%5Cint%5B1%5Ctimes%5Cfrac%7B1%7D%7Bn%2B1%7De%5E%7B%28n%2B1%29t%7D%5D%5C%2Cdt%5C%5C%5C%5CI%3D%5B%5Cfrac%7Bt%7D%7Bn%2B1%7De%5E%7B%28n%2B1%29t%7D%5D-%5B%5Cfrac%7B1%7D%7B%28n%2B1%29%5E%7B2%7D%7De%5E%7B%28n%2B1%29t%7D%5D)
Writing in terms of x
I=![[\frac{t}{n+1}e^{(n+1)t}]-[\frac{1}{(n+1)^{2}}e^{(n+1)t}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bt%7D%7Bn%2B1%7De%5E%7B%28n%2B1%29t%7D%5D-%5B%5Cfrac%7B1%7D%7B%28n%2B1%29%5E%7B2%7D%7De%5E%7B%28n%2B1%29t%7D%5D)
I=![[\frac{logx}{n+1}e^{(n+1)logx}]-[\frac{1}{(n+1)^{2}}e^{(n+1)logx}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Blogx%7D%7Bn%2B1%7De%5E%7B%28n%2B1%29logx%7D%5D-%5B%5Cfrac%7B1%7D%7B%28n%2B1%29%5E%7B2%7D%7De%5E%7B%28n%2B1%29logx%7D%5D)
I=![[\frac{logx}{n+1}e^{logx^{(n+1)}}]-[\frac{1}{(n+1)^{2}}e^{logx^{(n+1)}}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Blogx%7D%7Bn%2B1%7De%5E%7Blogx%5E%7B%28n%2B1%29%7D%7D%5D-%5B%5Cfrac%7B1%7D%7B%28n%2B1%29%5E%7B2%7D%7De%5E%7Blogx%5E%7B%28n%2B1%29%7D%7D%5D)
I=![[\frac{logx}{n+1} x^{(n+1)}]-[\frac{1}{(n+1)^{2}}x^{(n+1)}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Blogx%7D%7Bn%2B1%7D%20x%5E%7B%28n%2B1%29%7D%5D-%5B%5Cfrac%7B1%7D%7B%28n%2B1%29%5E%7B2%7D%7Dx%5E%7B%28n%2B1%29%7D%5D)
Thus,
Integration of I=
=![[\frac{logx}{n+1} x^{(n+1)}]-[\frac{1}{(n+1)^{2}}x^{(n+1)}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Blogx%7D%7Bn%2B1%7D%20x%5E%7B%28n%2B1%29%7D%5D-%5B%5Cfrac%7B1%7D%7B%28n%2B1%29%5E%7B2%7D%7Dx%5E%7B%28n%2B1%29%7D%5D)
38 + 4 = 42 (1 year); 42 + 4 = 46 (2 years); 46 + 4 = 50 (3 years); 50 + 4 = 54 (4 years); 54 + 4 = 58 (5 years)
45.5 + 2.5 = 48 (1 year); 48 + 2.5 = 50.5 (2 years); 50.5 + 2.5 = 53 (3 years); 53 + 2.5 = 55.5 (4 years); 55.5 + 2.5 = 58 (5 years)
It will take 5 years before the trees are the same height, 58 inches.