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Ede4ka [16]
3 years ago
10

If the strength of the magnetic field at A is 10 units, the strength of the magnetic field at B is _____. 640 units 6.4 units 2.

5 units 1.25 units NEXT
Chemistry
2 answers:
MrMuchimi3 years ago
5 0

Answer:

2.5 units

Explanation:

dezoksy [38]3 years ago
4 0
Answer : Option C) 2.5 units

Explanation : For calculating the strength of a unknown magnetic field in comparison with the given magnetic field we can use the magnetic formula as;

\frac{ S_{1}}{S_{2}} =  \frac{ (D_{1}^{2}) }{(D_{2}^{2})} .

On substituting the values we get; 

\frac{10}{x}  =  \frac{4^{2}}{2^{2}} ;

On solving we get the magnetic B field strength as 2.5 units


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4 0
3 years ago
A solution is made by adding 35.5 mL of concentrated hydrochloric acid ( 37.3 wt% , density 1.19 g/mL1.19 g/mL ) to some water i
erastova [34]

Answer:

1.73 M

Explanation:

We must first obtain the concentration of the concentrated acid from the formula;

Co= 10pd/M

Where

Co= concentration of concentrated acid = (the unknown)

p= percentage concentration of concentrated acid= 37.3%

d= density of concentrated acid = 1.19 g/ml

M= Molar mass of the anhydrous acid

Molar mass of anhydrous HCl= 1 +35.5= 36.5 gmol-1

Substituting values;

Co= 10 × 37.3 × 1.19/36.5

Co= 443.87/36.6

Co= 12.16 M

We can now use the dilution formula

CoVo= CdVd

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Vd= volume of dilute acid = 250ml

Substituting values and making Cd the subject of the formula;

Cd= CoVo/Vd

Cd= 12.16 × 35.5/250

Cd= 1.73 M

7 0
3 years ago
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