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Bond [772]
3 years ago
7

A gas occupies 800ml at a temperature of 27C. What is the volume at 132C?

Chemistry
1 answer:
pishuonlain [190]3 years ago
3 0

V
1
​
/T
1
​
=V
2
​
/T
2
​

(900.0 mL) / (300.0 K) = (x) / (405.0 K); x = 1215 mL.

Change the 900 to 800, and the 300 to 27, then change the 405 to 132. And solve
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How much thermal energy (q) is required to heat 15.2g of a metal (specific heat=0.397J/C) from 21.0C to 40.3C? Show steps please
Elena L [17]
Q = ?

Cp = 0.397 J/ºC

Δt =  40.3 - 21.0<span> => 19.3</span><span> ºC</span>

m = 15.2 g

Q = m x Cp x Δt

Q = 15.2 x 0.397 x 19.3

Q ≈ 116.46 J

<span>hope this helps! </span>
7 0
4 years ago
(a) The student dissolves the entire impure sample of CuSO4(s) in enough distilled water to make 100.mL of solution. Then the st
Talja [164]

Answer:

Explanation:

Given parameters :

Volume of solution  = 100mL

Absorbance of solution  = 0.30

Unknown:

Concentration of CuSO₄ in the solution = ?

Solution:

There is relationship between the absorbance and concentration of a solution. They are directly proportional to one another.

A graph of absorbance against concentration gives a value of 0.15M at an absorbance of 0.30.

The concentration is 0.15M

Also, we can use:  Beer-Lambert's law;

                    A  = ε mC l

where εm is the molar extinction coefficient

             C is the concentration

             l is the path length

Since the εm is not given and assuming path length is 1;

         Then we solve for the concentration.

3 0
3 years ago
Hurry answer this pls so i can pass
makvit [3.9K]
A I took the test already and it’s A for sure because the syrup has less water in it. It sucks the water out of the egg.
4 0
3 years ago
Read 2 more answers
1.00-degree increase on the Celsius scale is equivalent to a 1.80-degree increase on the Fahrenheit scale. The temperature of a
castortr0y [4]
48.0°C×1.80 = 86.4°F
6 0
3 years ago
When methane, CH4, is combusted, it produces carbon dioxide, CO₂, according to the unbalanced equation: CH4 +0₂ - CO₂ + H₂O.
nevsk [136]

The balanced equation will be CH_4 + 2O_2 --- > CO_2 + 2H_2O

<h3>Stoichiometric problems</h3>

The balanced equation of the reaction would be as follows:

CH_4 + 2O_2 --- > CO_2 + 2H_2O

The mole ratio of methane to carbon dioxide is 1:1.

10 grams of methane will give 10/16 = 0.625 moles

0.625 moles of carbon dioxide would give 0.625 x 44.01 = 27.506 grams.

Thus, 10 grams of methane will produce approximately 27 grams of carbon dioxide stoichiometrically.

The reaction obeys the law of conservation of mass because the atoms of all the elements before and after the reaction are balanced.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

3 0
2 years ago
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