1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
laila [671]
3 years ago
11

Warm air lifted over a moving cold air mass will produce a front

Chemistry
2 answers:
valina [46]3 years ago
7 0

Answer:

Warm air lifted over a moving cold air mass will produce a cold front

crimeas [40]3 years ago
4 0

Answer:

cold

Warm air lifted over a moving cold air mass will produce a _____ front.

You might be interested in
Why is it difficult for countries to reduce emissions of carbon dioxide
Natalka [10]

Answer:

Curbing global carbon dioxide emissions has been a challenge, primarily because they are being driven higher by countries with low per capita emissions.

Explanation:

"just trust me bro"

3 0
3 years ago
What are some benefits of eating apples??
Lisa [10]
Apples are rich in fiber and antioxidants. Eating them is linked to a lower risk of many chronic conditions, including diabetes, heart disease, and cancer. Apples may also promote weight loss and improve gut and brain health.
5 0
2 years ago
Read 2 more answers
What is the pH of pure water at 40.0°C if the Kw at this temperature is 2.92 - 10-147 OA) 6.767 O B) 0 465 O c) 7.000 OD) 7 233
Sergeeva-Olga [200]

Answer:

PH= 6.767     (answer is the A option)

Explanation:

first we need to correct the value in Kw at this temperature is 2.92*10^-14

so, in this case we have that:

Kw=2.92*10^-14 M²

[ H3O^+] [ H3O^+]

[H_{3}O^{+}  ] [OH^{-}  ] = Kw = 2.92*10^{-14} M^{2}   \\\\

at 40ºC

[H_{3}O^{+}  ] = [OH^{-}  ]

[H_{3}O^{+}  ]^{2} = 2.92*10^{-14} M^{2}

[H_{3}O^{+}  ] = (2.92*10^{-14})^{1/2} = 1.71*10^{-7} M

PH= -log10[H_{3}O^{+}  ] = -log10(1.71*10^{-7} ) = 6.767

7 0
3 years ago
6
Vanyuwa [196]

Answer:

If the volume of a gas increased from 2 to 6 L while the temperature was held constant, <u><em>the  pressure of the gas decreased by a factor of 3.</em></u>

Explanation:

Boyle's law that says "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure." This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or

P * V = k

To obtain the proportionality factor k you must make the quotient:

k=\frac{V2}{V1} =\frac{6 L}{2 L}

k= 3

This means that <u><em>if the volume of a gas increased from 2 to 6 L while the temperature was held constant, the  pressure of the gas decreased by a factor of 3.</em></u>

4 0
3 years ago
A. True <br> b. False a chemical species is either an acid or a base, it cannot function as both
ivann1987 [24]
False They can function as both. An example is Aluminium Oxide. These kind of substances are called "Amphoteric", they can behave as both acids and bases.
3 0
3 years ago
Other questions:
  • As an environmental engineer how would you apply the process of separating mixtures to clean up a polluted beach? What would you
    13·1 answer
  • What kind of chemical bonds are represented by the product in the following diagram?
    13·1 answer
  • What does it mean to be recyclable? What are a few recyclable materials?
    9·2 answers
  • Determine the molar mass of the ionic compound sodium hydroxide. (1 point)
    7·1 answer
  • An isotope with a mass number of 193 has 116 neutrons. What is the atomic number of this
    5·1 answer
  • What kind of object has an indefinite shape and indefinite volume?<br> IH
    14·1 answer
  • True or false 12,785.000 has five significant digits.
    14·2 answers
  • 3. What are vaccines? Are there different types?​
    5·2 answers
  • Is it possible to make new water
    11·2 answers
  • How many of each element would you find in AI(NO3)3?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!