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Aneli [31]
3 years ago
8

Can someone help me define “Celestial roles”? I can’t find it in my textbook, and when I look it up it just shows Marvel stuff.

I’m supposed to define certain words and I have no idea what celestial roles means.
Physics
2 answers:
Scrat [10]3 years ago
8 0

Answer:

Hi sister

I'm Rohan I'm new in Brainly

Please inbox me sister

Explanation:

The Celestials collectively shaped the cosmos in order to create life throughout the universe, and were indirectly responsible for the emergence of the Multiverse itself. One Celestial was even able to warp reality on a pocket-dimensional scale, threatening to alter the entire universe.

and ur looking gorgeous sister

bye

Soloha48 [4]3 years ago
4 0

Answer:

iam not getting about celestial roles ,here is the meaning of celestial

Explanation:

The first is something living such as an alien or an angel, whereas the latter is an inanimate object such as a star or a planet. Both, however, are from the sky. The word celestial is primarily used to describe things that have to do with the heavens such as angels, spirits, stars and planets.

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Kate is working on a project in her tech education class. She plans to assemble a fan motor. Which form of energy does the motor
andreyandreev [35.5K]

Motion Energy

I am writing this so it can be more than 20 letters

7 0
4 years ago
A toy plane is flying in a horizontal circle by being attached to a 0.75 meter string. The plane has a mass of 101.7 grams and m
nadezda [96]

Answer:

F = 2,894 N

Explanation:

For this exercise let's use Newton's second law

      F = m a

The acceleration is centripetal

     a = v² / r

Angular and linear variables are related.

     v = w r

Let's replace

     F = m w² r

The radius r and the length of the rope is related

    cos is = r / L

    r = L cos tea

Let's replace

    F = m w² L cos θ

Let's reduce the magnitudes to the SI system

     m = 101.7 g (1 kg / 1000g) = 0.1017 kg

      θ = 5 rev (2π rad / rev) = 31,416 rad

     w =  θ / t

     w = 31.416 / 5.1

     w = 6.16 rad / s

     F = 0.1017 6.16² 0.75 cos  θ

     F = 2,894 cos  θ

The maximum value of F is for  θ equal to zero

     F = 2,894 N

7 0
3 years ago
What are some similarities and differences between elements, compounds, and mixtures?
Lina20 [59]
T<span>he </span>similarities between compounds<span> and </span>mixtures<span> are that they are both made up of two or more </span>elements<span> and that they could both be separated and then mixed with different </span>elements<span> to make a new </span>mixture<span> and </span>compound<span>.

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4 0
3 years ago
Read 2 more answers
A plastic film moves over two drums. During a 4-s interval the speed of the tape is increased uniformly from v0 = 2ft/s to v1 =
Ratling [72]

Answer:

Question 1)

a) The speed of the drums is increased from 2 ft/s to 4 ft/s in 4 s. From the below kinematic equations the acceleration of the drums can be determined.

v_1 = v_0 + at \\4 = 2 + 4a\\a = 0.5~ft/s^2

This is the linear acceleration of the drums. Since the tape does not slip on the drums, by the rule of rolling without slipping,

v = \omega R\\a = \alpha R

where α is the angular acceleration.

In order to continue this question, the radius of the drums should be given.

Let us denote the radius of the drums as R, the angular acceleration of drum B is

α = 0.5/R.

b) The distance travelled by the drums can be found by the following kinematics formula:

v_1^2 = v_0^2 + 2ax\\4^2 = 2^2 + 2(0.5)x\\x = 12 ft

One revolution is equal to the circumference of the drum. So, total number of revolutions is

x / (2\pi R) = 6/(\pi R)

Question 2)

a) In a rocket propulsion question, the acceleration of the rocket can be found by the following formula:

a = \frac{dv}{dt} = -\frac{v_{fuel}}{m}\frac{dm}{dt} = -\frac{13000}{2600}25 = 125~ft/s^2

b) a = -\frac{v_{fuel}}{m}\frac{dm}{dt} = - \frac{13000}{400}25 = 812.5~ft/s^2

5 0
4 years ago
The position of a particle moving along the x axis depends on the time according to the equation x = ct² - bt³, where x is in me
Kamila [148]

Answer:

(a) \frac{m}{s^2}

(b) \frac{m}{s^3}

(c) 1 s

(d) 20 m

(e) 1 m

(f) 0\frac{m}{s}

(g) -12\frac{m}{s}

(h) -36\frac{m}{s}

(i) -72\frac{m}{s}

(j) -6\frac{m}{s^2}

(k) -18\frac{m}{s^2}

(l) -30\frac{m}{s^2}

(m) -42\frac{m}{s^2}

Explanation:

Since <em>x</em> is measured in meters and <em>t</em> in seconds, constants <em>a </em>and <em>b</em> must have units that gives meters when multiplied by square and cubic seconds respectivly, so that would mean \frac{m}{s^2} for <em>a </em>and \frac{m}{s^3} for <em>b</em>.

We can get the velocity <em>v </em>equation by deriving the position with respect to <em>t</em>, which gives:

v=6*t-6*t^2

And the acceleration <em>a</em> equation by deriving again:

a=6-12*t

Now for getting the maximun position between 0 and 4, we must find to points where the positions first derivate is equal to cero and evaluate those points. That is <em>v=0</em>, which gives

6*t-6*t^2=0\\6t*(1-t)=0\\t=0 or t=1

For <em>t = 0</em>,<em> x = 0</em> so the maximun position is archieved at 1 second, which gives <em>x = 1 meter</em>.

For obtaining it's displacement <em>r</em>, we can integrate the velocity from 0 seconds to 4 seconds, which gives the mean value of the position in that interval:

r=\frac{1}{4}*(2*4^3-3*4^2)m\\r= 20m

For the remaining questions, we just replace the values of <em>t</em> on the respective equations.

8 0
4 years ago
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