Answer:
Explanation:
Distance between ship and enemy ship
= 500 + 610
= 3110 m
Range of projectile
R = u² sin2θ / g
= (250x 250 sin 150) / 9.8
= 3188m
The projectile falls within a distance of 3188 - 3110 = 78 m from enemy ship
Height of mountain = 1800 m
We shall find the height of projectile when its horizontal displacement is 2500m
x = 2500 , y = ?
u = 2500 ,
y = x / cos θ - .5 g x² /u²cos² θ
9660 - 7315 m
= 2345 m
It is within 545 m from mountain peak .
It’s D the time period within pendulums are constant, distance is always measured with kilometers within cities and basic unit is always seconds.
Answer:
<h2>B. 20°</h2>
Explanation:
Range in projectile is defined as the distance covered in the horizontal direction. It is expressed as R = U²sin2Ф/g
U is the initial velocity of the body (in m/s)
Ф is the angle of projection
g is the acceleration due to gravity.
Given U = 14m/s, g = 9.8m/s and range R = 15 m
we will substitute this value into the formula to get the projection angle Ф as shown;
15 = 15²sin2Ф/9.8
15*9.8 = 15²sin2Ф
147 = 225sin2Ф
sin2Ф = 147/225
sin2Ф = 0.6533
2Ф = sin⁻¹0.6533
2Ф = 40.79°
Ф = 40.79°/2
Ф = 20.39° ≈ 20°
Hence, the range is greatest at angle 20°
Increases exponentially is your correct answer
