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Vera_Pavlovna [14]
3 years ago
11

A toy plane is flying in a horizontal circle by being attached to a 0.75 meter string. The plane has a mass of 101.7 grams and m

akes five circular revolutions in 5.1 seconds. Find the tension force acting upon the plane. X Newtons Enter a number Determine the angle at which the string is pulled below the horizontal. degrees
Physics
1 answer:
nadezda [96]3 years ago
7 0

Answer:

F = 2,894 N

Explanation:

For this exercise let's use Newton's second law

      F = m a

The acceleration is centripetal

     a = v² / r

Angular and linear variables are related.

     v = w r

Let's replace

     F = m w² r

The radius r and the length of the rope is related

    cos is = r / L

    r = L cos tea

Let's replace

    F = m w² L cos θ

Let's reduce the magnitudes to the SI system

     m = 101.7 g (1 kg / 1000g) = 0.1017 kg

      θ = 5 rev (2π rad / rev) = 31,416 rad

     w =  θ / t

     w = 31.416 / 5.1

     w = 6.16 rad / s

     F = 0.1017 6.16² 0.75 cos  θ

     F = 2,894 cos  θ

The maximum value of F is for  θ equal to zero

     F = 2,894 N

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What might cause convection currents in a hot spring?
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A metal object with a mass of 19g is heated to 96c, then transferred to a calorimeter containg 75g of water at 18c. the water an
avanturin [10]

Let us say that Cp is the specific heat of the metal object. Then we do a heat balance (heat lost by metal = heat gained by water):

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6 0
3 years ago
Read 2 more answers
-
Sergeeva-Olga [200]

Answer:

(a) 32.5 kgm/s

(b) 32.5 Ns

(c) 10.8 N

Explanation:

The change in momentum can be calculated from the definition of linear momentum:

\Delta p=\Delta (mv)= m \Delta v\\\\\Delta p= (5.00kg)(9.75m/s-3.25m/s)\\\\\Delta p=32.5kgm/s

Then, the change in momentum of the body is of 32.5 kgm/s (a).

Now, from the impulse-momentum theorem, we know that the change in momentum of a body \Delta p is equal to the impulse I exerted to it. So, the impulse produced by the force equals 32.5 kgm/s (or 32.5 Ns) (b).

Finally, since we know the value of the impulse and the interval of time, we can easily solve for the magnitude of the force:

I=F\Delta t\\\\\implies F=\frac{I}{\Delta t}\\\\F=\frac{32.5Ns}{3.0s}\\\\F=10.8N

It means that the magnitude of the force is of 10.8N (c).

8 0
3 years ago
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An electromagnetic wave is traveling the +y direction. The maximum magnitude of the electric field associated with the wave is E
cluponka [151]

Answer:

0.83x10^-9 T

Direction is towards +z axis.

Explanation:

E = cB

E = magnitude of electrical 0.25 Em

c = speed of light in a vacuum 3x10^8 m/s

Therefore,

B = E/c = 0.25 ÷ 3x10^8

B = 0.83x10^-9 T

Magnetic fueld of a EM wave acts perpendicularly to its electric field, therefore it's direction is towards the +Z axis

3 0
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