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Vera_Pavlovna [14]
3 years ago
11

A toy plane is flying in a horizontal circle by being attached to a 0.75 meter string. The plane has a mass of 101.7 grams and m

akes five circular revolutions in 5.1 seconds. Find the tension force acting upon the plane. X Newtons Enter a number Determine the angle at which the string is pulled below the horizontal. degrees
Physics
1 answer:
nadezda [96]3 years ago
7 0

Answer:

F = 2,894 N

Explanation:

For this exercise let's use Newton's second law

      F = m a

The acceleration is centripetal

     a = v² / r

Angular and linear variables are related.

     v = w r

Let's replace

     F = m w² r

The radius r and the length of the rope is related

    cos is = r / L

    r = L cos tea

Let's replace

    F = m w² L cos θ

Let's reduce the magnitudes to the SI system

     m = 101.7 g (1 kg / 1000g) = 0.1017 kg

      θ = 5 rev (2π rad / rev) = 31,416 rad

     w =  θ / t

     w = 31.416 / 5.1

     w = 6.16 rad / s

     F = 0.1017 6.16² 0.75 cos  θ

     F = 2,894 cos  θ

The maximum value of F is for  θ equal to zero

     F = 2,894 N

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I understand your problem, that question is pretty hard. But I found some information that I think you should read. This can get your problem done quickly.

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