Answer:
dont mind me just grinding for points
Step-by-step explanation:
Answer:
Results:
0.1432
0.0045
0.0905
0.0483
Step-by-step explanation:
Step a:
P(A or 10, A or 10) = 20/52 * 19/51 = 5/13 / 19/51 = 95/663 = 0.1432
Step b:
P(A A) = 4/52 * 3/51 = 1/13 * 1/17 = 1/221 = 0.0045
Step c:
P(10 10) = 16/52 * 15/51 = 4/13 * 5/17 = 20/221 = 0.0905
Step d:
P(A 10 or 10 A) = 2 * 4/52 * 16/51 = 2/13 * 16/51 = 32/663 = 0.0483
As well we get the probability by subtracting a, b and c:
P(blackjack): 0.1432 - 0.0905 - 0.0045 = 0.0482
The answer: d. < 1 and < 8
Answer:
(-6,4)
Step-by-step explanation:
The equations are:
Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:
Now we can solve for y:
So plugging in y = 4 into an equation and solving for x, we have:
So y = 4 corresponds to x = 6 & x = -6
The pairs would be
(6,4) & (-6,4)
<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>
The question is incomplete. Here is the complete question.
As a part of city building refurbishment project, architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.
The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?
Answer: 81 feet by 153 feet
Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.
In the refurbishment project, the unit scale is given by
1 inch = 9 feet
So, the dimensions of the new park in actual dimensions would be
1 inch = 9 feet
9 inches = x
x = 9.9
x = 81 feet
1 inch = 9 feet
17 inches = y
y = 17.9
y = 153 feet
The actual dimensions of the new park are 81 feet by 153 feet.
