Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.
Answer:
27
Step-by-step explanation:
sub in the letters with the given number in brackets
= (9) + 6(3)
= (9) + 18
= 27
Answer:
11
n²
Step-by-step explanation:
Given
= 
× 
× 
= 11 × × n²
= 11n²
I believe it is 48.
0+3=3
3+5=8
8+7=15
15+9=24
24+11=35
35+13=48
Answer:
V = D/M
Step-by-step explanation:
divide both sides by M to isolate V
