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Alex777 [14]
3 years ago
11

If a = -9 and b= -4, what is the value of a + b? -5, 5, -13, 13.

Mathematics
2 answers:
kirill115 [55]3 years ago
8 0

Answer:

-13

Step-by-step explanation:

simply add

garik1379 [7]3 years ago
8 0

Answer:

Step-by-step explanation:

a+b

-9+(-4)

-9-4

-13

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I think of a number, add 8 to it and the result is 14. Find the number​
Leya [2.2K]

Answer:

6

Step-by-step explanation:

The equation for this would be:

n+8=14, since we are adding 8 to a number and getting 14

To solve, isolate the variable n, by subtracting 8 from both sides

n+8=14

n+8-8=14-8

n=6

The number is 6

3 0
3 years ago
Read 2 more answers
(I do brainliest.) slope intercept form... [show ya work plz]
eduard

Answer:

y = 3x+2

Step-by-step explanation:

(3,7) (6,9) Y2=9 Y1=7  X2=6 X1=3

M = 9-7/6/3

2/3

3 0
3 years ago
No dia da festança, bianca comprou dos pasteis por $5,20, duas maçãs do amor por $ 3,40 e dois refrigerantes por $7,60. Quanto b
atroni [7]

Responder:

$ 16,2

Explicação passo a passo:

No dia da festa, Bianca comprou os pastéis por US $ 5,20, duas maçãs do amor por US $ 3,40 e dois refrigerantes por US $ 7,60. Quanto bianca você gastou?

O valor gasto por Bianca é a soma de todos os itens que ela comprou:

Pastelaria = $ 5,20

Maçãs do amor = $ 3,40

Refrigerantes = $ 7,60

A soma da soma dá o valor gasto de Bianca:

Doces + Maçãs do Amor + Refrigerante

$ (5,20 + 3,40 + 7,60)

= $ 16,2

5 0
3 years ago
Grace wants to find the probability of a family of 3 children having 2 boys and 1 girl. Use a tree diagram to list the possibili
pychu [463]

Answer:

Step-by-step explanation:

My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.

5 0
2 years ago
16.4.57 Question Help A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill You bl
Rudiy27

Answer:

$ 7.7

Step-by-step explanation:

Given,

There are 18 $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill,

Total number of bills = 18 + 10 + 8 + 3 + 1 = 40,

\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

Thus,

The probability of $ 1 = \frac{18}{40}

The probability of $ 5 = \frac{10}{40}

The probability of $ 10 = \frac{8}{40}

The probability of $ 20 = \frac{3}{40}

The probability of $ 100 = \frac{1}{40}

If a bill is selected randomly,

The expected value of the bill

=\frac{18}{40}\times 1+\frac{10}{40}\times 5+\frac{8}{40}\times 10+\frac{3}{40}\times 20+\frac{1}{40}\times 100

=\frac{18+50+80+60+100}{40}

=\frac{308}{40}

= $ 7.7

5 0
3 years ago
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