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Brut [27]
4 years ago
12

Which factor is the most imortant in performing the activities of daily living

Physics
1 answer:
wariber [46]4 years ago
7 0

Answer:

Muscular endurance is the most important factor in performing the activities of daily living.

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A soda has a volume of 560 mL and a density of 3.2 g/mL. What is the mass?
kolbaska11 [484]
The correct answer is: 1792g or 1800g.

(When you round it)
8 0
3 years ago
What do scientists use to determine the temperature of a star?
Nastasia [14]

Answer:

Measure the brightness of a star through two filters and compare the ratio of red to blue light. Compare to the spectra of computer models of stellar spectra of different temperature and develop an accurate color-temperature relation.

7 0
3 years ago
A compact disc (CD) stores music in a coded pattern of tiny pits 10−7m deep. The pits are arranged in a track that spirals outwa
andreev551 [17]

(a) 50 rad/s

The angular speed of the CD is related to the linear speed by:

\omega=\frac{v}{r}

where

\omega is the angular speed

v is the linear speed

r is the distance from the centre of the CD

When scanning the innermost part of the track, we have

v = 1.25 m/s

r = 25.0 mm = 0.025 m

Therefore, the angular speed is

\omega=\frac{1.25 m/s}{0.025 m}=50 rad/s

(b) 21.6 rad/s

As in part a, the angular speed of the CD is given by

\omega=\frac{v}{r}

When scanning the outermost part of the track, we have

v = 1.25 m/s

r = 58.0 mm = 0.058 m

Therefore, the angular speed is

\omega=\frac{1.25 m/s}{0.058 m}=21.6 rad/s

(c) 5550 m

The maximum playing time of the CD is

t =74.0 min \cdot 60 s/min = 4,440 s

And we know that the linear speed of the track is

v = 1.25 m/s

If the track were stretched out in a straight line, then we would have a uniform motion, therefore the total length of the track would be:

d=vt=(1.25 m/s)(4,440 s)=5,550 m

(d) -6.4\cdot 10^{-3} rad/s^2

The angular acceleration of the CD is given by

\alpha = \frac{\omega_f - \omega_i}{t}

where

\omega_f = 21.6 rad/s is the final angular speed (when the CD is scanned at the outermost part)

\omega_i = 50.0 rad/s is the initial angular speed (when the CD is scanned at the innermost part)

t=4440 s is the time elapsed

Substituting into the equation, we find

\alpha=\frac{21.6 rad/s-50.0 rad/s}{4440 s}=-6.4\cdot 10^{-3} rad/s^2

5 0
3 years ago
Read 2 more answers
Which statements accurately describe elements? Check all that apply
GalinKa [24]

Answer:

Elements are made up of only one type of atom. Each element has a unique chemical symbol. Elements can be identified by their atomic number.

7 0
3 years ago
What is the weight of a 20kg stone?​
worty [1.4K]

Answer: w = 200N

Explanation:

w = mg

m = 20kg

g = 10m/s^ (approximately)

w = 20kg . 10m/s^

w = 200N

5 0
3 years ago
Read 2 more answers
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