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Ede4ka [16]
4 years ago
11

Which type of central heating system involves fans and ducts to circulate warm air?

Physics
2 answers:
attashe74 [19]4 years ago
8 0

Answer: forced-air heating

Explanation:

satela [25.4K]4 years ago
3 0
Forced-Air would be the type of central heating system 
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A motorboat traveling on a straight course slows
never [62]

Answer:

2.572 m/s²

Explanation:

Convert the given initial velocity and final velocity rates to m/s:

  • 65 km/h → 18.0556 m/s
  • 35 km/h → 9.72222 m/s

The motorboat's displacement is 45 m during this time.

We are trying to find the acceleration of the boat.

We have the variables v₀, v, a, and Δx. Find the constant acceleration equation that contains all four of these variables.

  • v² = v₀² + 2aΔx

Substitute the known values into the equation.

  • (9.72222)² = (18.0556)² + 2a(45)
  • 94.52156173 = 326.0046914 + 90a
  • -231.4831296 = 90a
  • a = -2.572

The magnitude of the boat's acceleration is |-2.572| = 2.572 m/s².

3 0
3 years ago
The total momentum of two marbles before a collision is 0.06 kg-m / s. no outside forces act on the marbles. what is the total m
SpyIntel [72]
Hi my friend, since momentum is always conserved without external forces, the momentum after the collosion will still be 0.06 kg*m/s. Hope it helps☺
4 0
3 years ago
How does the image distance (di) of a convex lens compare with the image distance of a concave lens?
SVETLANKA909090 [29]
Correct Answer is A.
8 0
3 years ago
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The voltage V in a circuit that satisfies the law V = IR is slowly dropping as the battery wears out. At the same time, the resi
Anastasy [175]

Answer:

-0.5\times 10^{-4} A/s

Explanation:

We are given that

\frac{dV}{dt}=-0.01 V/s

R=600 ohms

I=0.04 A

\frac{dR}{dt}=0.5ohm/s

V=IR

\frac{dV}{dt}=\frac{\partial V}{dI}\frac{dI}{dt}+\frac{\partial V}{dR}\frac{dR}{dt}

\frac{dV}{dt}=R\frac{dI}{dt}+I\frac{dR}{dt}

Substitute the values

-0.01=600\times \frac{dI}{dt}+0.04\times 0.5

-0.01-0.04\times 0.5=600\frac{dI}{dt}

-0.03=600\frac{dI}{dt}

\frac{dI}{dt}=\frac{-0.03}{600}=-0.5\times 10^{-4}A/s

5 0
4 years ago
Convert the orbital period 27.32 days into units of seconds
maks197457 [2]

Answer:

2360448seconds

Explanation:

Dimensional analysis is attached.

3 0
2 years ago
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