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vampirchik [111]
3 years ago
9

Wil-E-Coyote drops a bowling ball off a cliff to try to catch the Roadrunner. The cliff is

Physics
1 answer:
PtichkaEL [24]3 years ago
8 0

Answer:

t = 5.19 s

Explanation:

We have,

Height of the cliff is 132 m

It is required to find the time taken by the ball to fall to the ground. Let t is the time taken. So, using equation of kinematics as :

y=ut+\dfrac{1}{2}gt^2\\\\\text{since}\ u=0\\\\y=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2y}{g}}\\\\t=\sqrt{\dfrac{2\times 132}{9.8}}\\\\t=5.19\ s

So, it will take 5.19 seconds to fall to the ground.

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Two stationary positive point charges, charge 1 of magnitude 3.90 nC and charge 2 of magnitude 1.80 nC, are separated by a dista
soldi70 [24.7K]

Answer:

v = 7793150 m/s

Explanation:

First, we are going to calculate the electrical potential in the point middle between the two charges

Remember that the electrical potential can be calculated as:

v = \frac{kQ}{r}

                 Where     k = 8.9874 x 10^{9} \frac{Nm^{2} }{C^{2} }

and it is satisfy the superposition principle, thus

v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.23} +  \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.23}

v = 222.73v

The electrical potential at 10 cm from charge 1 is:

v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.1} +  \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.36}

v = 395.44 v

Since the work - energy theorem, we have:

q\Delta v = \frac{mv^{2} }{2}

                     where q is the electron's charge and m is the electron's mass

Therefore:

v = \sqrt{\frac{2q\Delta v}{m} }

v = 7793150 m/s

6 0
3 years ago
You observe three carts moving to the left. Cart A moves to the left at nearly constant speed. Cart B moves to the left, gradual
Lady bird [3.3K]

Answer:cart B

Explanation:

For cart A speed is constant therefore there is no acceleration because acceleration is rate of change of velocity

thus there is no net force

For cart B there is change in velocity in the left direction , so there is net acceleration towards left

Force=mass\times acceleration

so there is net force in the left direction

For cart C there is decrease in velocity i.e. negative acceleration or deceleration . Therefore there is a net force towards right which opposes the motion                

6 0
3 years ago
Match each type of wave to the way it moves. transverse wave longitudinal wave electromagnetic wave back and forth at right angl
marta [7]

Transverse wave = at right angles to the direction of the motion of the wave

in transverse wave medium particles will move perpendicular to the direction of motion of medium particles

they all are perpendicular to wave always

Longitudinal wave = back and forth in the direction of the motion of the wave

in longitudinal waves medium particles will move in the direction of wave and the motion is always in back and forth type

electromagnetic wave = alternating waves moving at right angles to each other

electromagnetic waves are combination of electric field and magnetic field which oscillates perpendicular to wave as well as they are perpendicular to each other

8 0
3 years ago
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Newton's first law of motion. An object in motion tends to stay in motion. Since there is no friction in space to slow it down it just keeps going
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3 years ago
Answer pls quick or dont i dk what to say
OLEGan [10]

Answer:

C!

Explanation:

Cold fronts generally advance at average speeds of 20 to 25 mph. toward the east — faster in the winter than summer — and are usually oriented along a northeast to southwest line.

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