Complete question is;
The polynomial -16t² + v_o(t) + s_o represents the height (in feet) of an object, where v_o is the initial vertical
velocity (in feet per second), s_o is the initial height of the object (in feet), and t is the time in seconds. Write a polynomial that represents the height of the object that has an initial velocity of 25 ft/s and initial height of 4ft. Then find the height of the object after 1 second.
Answer:
A) Polynomial is h(t) = -16t² + 25t+ 4
B) h(1) = 13 ft
Step-by-step explanation:
A) We are given;
h = -16t² + v_o(t) + s_o
Where;
v_o = the initial vertical velocity
s_o = the initial height of the object
t = the time
We are given;
v_o = 25 ft/s
s_o = 4 ft
Thus, polynomial that represents the height is;
h(t) = -16t² + 25t+ 4
B) after a time of 1 second, height is;
h(1) = -16(1²) + 25(1) + 4
h(1) = -16 + 25 + 4
h(1) = 13 ft
