Answer:
The magnitude of the electric field is 8.47 N/C
Explanation:
Given;
uniform charge density, λ = 100 nC/m³
inner radii of the cylinder, r = 1.0 mm and 3.0 mm
distance from the symmetry axis, R = 2.0 mm
Area = 2πrl
Area =2π(2 x 10⁻)l
Volume = A x d
d = Volume / Area
the magnitude of the electric field
Therefore, the magnitude of the electric field is 8.47 N/C
Answer:
1. 5.12068 × 1011 N/C away from the proton
Explanation:
The electric field produced by a single point charge is given by:
where
k is the Coulomb's constant
q is the magnitude of the charge
r is the distance from the charge
In this problem, we have:
is the charge of the proton
is the distance at which we want to calculate the field
is the Coulomb's constant
Substituting into the formula,
And the direction of the electric field produced by a positive charge is away from the charge, so the correct answer is
1. 5.12068 × 1011 N/C away from the proton
Answer:
friction coefficient on the rough road is 0.117
Explanation:
As we know that car is taking turn on flat rough road
So here we can say that required centripetal force for circular motion of car is due to frictional force
So we have
now we have
so we have