harge of uniform density (100 nC/m3) is distributed throughout a hollow cylindrical region formed by two coaxial cylindrical sur
1 answer:
Answer:
The magnitude of the electric field is 8.47 N/C
Explanation:
Given;
uniform charge density, λ = 100 nC/m³
inner radii of the cylinder, r = 1.0 mm and 3.0 mm
distance from the symmetry axis, R = 2.0 mm
Area = 2πrl
Area =2π(2 x 10⁻)l
Volume = A x d
d = Volume / Area
the magnitude of the electric field
Therefore, the magnitude of the electric field is 8.47 N/C
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A)
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Through Definition of Velocity, comes:
B)
Using the Velocity Hourly Equation in vertical direction, we have:
The angle of impact is given by:
If you notice any mistake in my english, please let me know, because i am not native.
It is a launch oblique, therefore the initial velocity in the vertical direction is zero. Space Hourly Equation in vertical, we have:
Through Definition of Velocity, comes:
B)
Using the Velocity Hourly Equation in vertical direction, we have:
The angle of impact is given by:
If you notice any mistake in my english, please let me know, because i am not native.
Answer:
The maximum length during the motion is
Explanation:
From the question we are told that
The mass is
The vertical spring length is
The unstretched length is
The initial speed is
The new length of the spring
The spring constant k is mathematically represented as
Where F is the force applied
y is the difference in weight which is
The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)
Now substituting values accordingly
The elastic potential energy is given as
where D is this the is the displacement
Since Energy is conserved the total elastic potential energy would be
Substituting value accordingly
So to obtain total length we would add the unstretched length
So we have