Answer:
Work done = 1716560.9 Joule
Explanation:
Given that a lunar module weighs 12 tons on the surface of the Earth.
How much work is done in propelling the module from the surface of the moon to a height of 60 miles?
Consider the radius of the moon to be 1100 miles (from the center of the moon) and its force of gravity to be one-sixth that of Earth.
1 ton = 907.185 kg
12 tons = 10886.22 kg
1 mile = 1.609 km
60 miles = 96.54 km
1100 miles = 1.609 × 1100 = 1769.9 km
Since it is from the surface of the moon, the work done = mgh
WD = 10886.22 × 9.8/6 × 96.54
WD = 1716560.9 J
Answer:
See the explanation below
Explanation:
To solve this problem we will take the definition of linear momentum, which tells us that momentum is equal to the product of mass by the velocity vector. Since velocity is a vector, we will take the right-hand movement as positive and the left-hand movement as negative, the left-hand members are taken as before the collision and the right-hand members as after the collision
ΣM1 = ΣM2
(m1*v1) + (m2*v1) = (m1*v2) + (m2*v2)
V1 = velocity before the collision [m/s]
V2 = velocity after the collision [m/s]
m1 and m2 = mass of the vehicles [kg]
Therefore:
(240*2.3) - (260*2.7) = - (240*2.9) + (260*2.1)
Resolving this arithmetic operation we will have:
720 - 702 = - 696 + 546
- 150 = - 150
We can see that before the crash and after the crash the momentum is preserved
Known :
l = 7 cm
w = 4 cm
Asked :
h = ...?
Answer :
V = B triangle × h (long)
35 = ½ × 4 × h × 7
35 = ½ × 28 × h
35 = 14 h
h = 35 ÷ 14
h = 2,5 cm
Sorry if I am wrong, I only study
Answer:
Explanation:
From the question we are told that:
Potential difference
New Capacitor
Generally the equation for Capacitor capacitance is mathematically given by
Generally the equation for New p.d' is mathematically given by