The billiard balls without replacement.
Let's say there are 10 billiard balls 5 red and 5 blue.
If you pick a blue ball on the first pick you had a 5/10 chance
Now your chances of getting a red are only 5/9.
What happened on the first pick affects what happens on the second (making it dependent)
Answer:
heart
Step-by-step explanation:
Answer:
The probability of selecting a solid black marbles both times;
P = 9/100
Attached is the completed question;
Step-by-step explanation:
Number of solid black marbles = 3
Total number of marbles = 10
The probability of selecting a solid black marble;
P1 = 3/10
With the assumption that the marbles are replaced before next selection.
The probability of selecting a solid black marbles both times;
P = P1 × P1 = 3/10 × 3/10 = 9/100
P = 9/100