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Mama L [17]
3 years ago
11

Ms. Rampal fills gum and trinket machines in front of grocery stores. In the trinket machine, there are two types of trinkets: n

ecklaces and rings. If Ms. Rampal puts 15 necklaces and 45 rings in a machine, what is the ratio of rings to all the trinkets in the machine? Write the ratio as a fraction in simplest form.
Mathematics
1 answer:
svlad2 [7]3 years ago
3 0

Answer:

3/4

Step-by-step explanation:

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If c (x) = 4x – 2 and d(x) = x2 + 5x, what is (cd) (x)
jolli1 [7]

c(x) = 4x - 2

d(x) = x^2 + 5x

4x - 2(x^2 + 5x)

<em><u>Using FOIL, distribute each term appropriately. </u></em>

4x^3 + 20x^2 - 2x^2 - 10x

<em><u>Combine like terms.</u></em>

4x^3 + 18x^2 - 10x is the simplified polynomials achieved when c(x) and d(x) are multiplied.

3 0
4 years ago
How can you use number patterns to find the least common multiple of 120 and 360?
Maslowich
Since 360 is a multiple of 120 then the answer is automatically 120. 120,240,360,480,600,720,840, and 960.
5 0
3 years ago
A construction worker drops a hammer while building the Grand Canyon skywalk 4,000ft above the Colorado River. Use the formula t
yan [13]

Answer:

15.8

Step-by-step explanation:

We are asked to find how many seconds it takes for an object to fall from a height of 4,000ft. We will use the given formula, t=h−−√4. Substituting h=4,000, we find

t=4000−−−−√4=15.8

So, the hammer reaches the river after 15.8 seconds.

7 0
3 years ago
Which expression is equivalent to 3(5 + 6)?
Anna [14]

Answer:

15+18

Step-by-step explanation:

3(5)+3(6)=15+18

5 0
4 years ago
Factor completely 2x^3 + 6x^2 + 10x + 30
andrezito [222]

Answer:

The factored expression is 2(x² + 5)(x + 3).

Step-by-step explanation:

Hey there!

We can use a factoring technique referred to as "grouping" to solve this problem.

Grouping is used for polynomials with four terms as a quick and easy factoring method to remove the GCF and get down to the initial terms that create the expression/function.

Grouping works in the following matter:

  1. Given equation: ax³ + bx² + cx + d
  2. Group a & b, c & d: (ax³ + bx²) + (cx + d)
  3. Pull GCFs and factors

Let's apply these steps to the given equation.

  1. Given equation: 2x³ + 6x² + 10x + 30
  2. Group a & b, c & d: (2x³ + 6x²) + (10x + 30)
  3. Pull GCFs and factors: 2x²(x + 3) + 10(x + 3)

As you'll see, we have a common term with both sides of the expression. This term, (x + 3), is a valuable asset to the factoring process. This is one of the factors for our expression.

Now, we use our GCFs to create another factor.

  1. List GCFs: 2x², 10
  2. Create a term: (2x² + 10)

Finally, we'll need to simplify this one by taking another GCF, 2.

  1. Pull GCF: 2(x² + 5)

Now that we have this term, we need to understand that this <em>could</em> also be factored further using imaginary numbers, but it is also acceptable to leave it in this form.

Therefore, we have our final factors: 2(x² + 5) and (x + 3).

However, when we factor, we place all of our terms together. This leaves us with the final answer: 2(x² + 5)(x + 3).

7 0
3 years ago
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