Answer:
D. I've watched Jurassic park uwu
Rate law for the given 2nd order reaction is:
Rate = k[a]2
Given data:
rate constant k = 0.150 m-1s-1
initial concentration, [a] = 0.250 M
reaction time, t = 5.00 min = 5.00 min * 60 s/s = 300 s
To determine:
Concentration at time t = 300 s i.e. ![[a]_{t}](https://tex.z-dn.net/?f=%5Ba%5D_%7Bt%7D)
Calculations:
The second order rate equation is:
![1/[a]_{t} = kt +1/[a]](https://tex.z-dn.net/?f=1%2F%5Ba%5D_%7Bt%7D%20%3D%20kt%20%2B1%2F%5Ba%5D)
substituting for k,t and [a] we get:
1/[a]t = 0.150 M-1s-1 * 300 s + 1/[0.250]M
1/[a]t = 49 M-1
[a]t = 1/49 M-1 = 0.0204 M
Hence the concentration of 'a' after t = 5min is 0.020 M
Answer:
2.0 grams per cubic centimeter
Explanation:
(You can refer to the DMV triangle to help you solve this!)
Density = Mass/Volume
Density = 4.0g/2.0cm3
Density = 2.0g/cm3
Hope this helps!!!
-Unicorns110504
*Please mark brainliest*
Answer:
the mass of the air in the room is 4.96512 kg ( in 0°C)