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d1i1m1o1n [39]
3 years ago
13

A carbon rod takes up 105 mL of space. With a density of 2.26 g/mL, what

Chemistry
1 answer:
aleksandrvk [35]3 years ago
8 0

Hey there!

Mass = ?

volume = 105 mL

Density = 2.26 g/mL

Therefore:

D = m / V

2.26 = m / 105

m = 2.26 * 105

m = 237.3 g

Hope this helps!

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It showed that atoms can be divided into smaller parts.

It showed that all atoms contain electrons.

Explanation:

The experiment carried out by J.J Thomson on the gas discharge tube by passing electric current through a tube filled with many different gases provided a good insight into the structure of an atom.

This experiment led to the development of the plum pudding model of the atom.

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Suppose 110.0 mL110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen
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Suppose 110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen fluoride dissolves in water to form 150.0 mL of an aqueous solution. 0.032 M is the concentration of the resulting hydrofluoric acid.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now write the balanced chemical equation

H₂ + F₂ → 2HF

<h3>What is Ideal Gas ?</h3>

An ideal gas is a gas that obey gas laws at all temperature and pressure conditions. It have velocity and mass but do not have volume. Ideal gas is also called perfect gas. Ideal gas is a hypothetical gas.

It is expressed as:

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Here,

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V = 110 ml = 0.11 L

T = 273 K   [At STP]

R = 0.0821   [Ideal gas constant]

Now put the values in above expression

PV = nRT

1 atm × 0.11 L = n × 0.0821 L.atm/ K. mol × 273 K

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<h3>How to find the concentration of resulting solution ? </h3>

To calculate the concentration of resulting solution use the expression

C = \frac{n}{V}

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C) Metaphoric

This is the correct answer.

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In air, beta particles with an energy of 0.5 MeV have a range of roughly one meter; the range is energy-dependent.

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