15x²+16x+4 =0 (ax² +bx +c=0)
Δ = b²-4ac =256 - 4×15×4 =16
x1 = (-b+√Δ) / 2a = (-16+√16) / 30 =( -16+4) / 30 = -12/30 = - 2/5
x2 = (-b -√Δ) / 2a = (-16 -√16) / 30 = (-16 -4) /30 = -20/30 = -2/3
Answer: 40
Step-by-step explanation:
Since 40 could be = 1 x 40, 2 x 20, 4 x 10, or 5 x 8.
The Factors of 40 will therefore be: 1, 2, 4, 5, 8, 10, 20, 40.
The Prime factor then is: 2, 2, 2, 5
Multiplying them together gives 40.
Answer:
1/15
Step-by-step explanation:
(1). <em>Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD (Least Common Denominator). </em>
So lets do step one now, the LCD is 15 so we have to make both denominators agree on one number, so 15 is the number both denominators agree on.
Solve:
2*3/5*3 - 1*5/3*5
(2). <em>Complete the multiplication.</em>
6/15 - 5/15
(3). <em>The two fractions now have like denominators so you can subtract the numerators.</em>
6 - 5 / 15 - 15 = 1/15
*Pro tip:
<em>The denominator doesn't change and stays the same. So you don't </em>
<em>subtract the 15 by 15.</em>
(4). <em>Then you'll get the answer and then if you can simplify then simplify.</em>
<em />
The Answer is 1/15, and cannot be simplified.
So the answer is 1/15
Hope this helps!
Total liters of water needed = number of attendee x water consumption/attendee wherenumber of attendee = 7000 attendeewater consumption/attendee = 0.5litre of water/attendeetotal = 7000 x 0.5 litre = 3500 litrescomputing the water requirement per 200 litre containerwater requirement in the event = 3500 litres/200 litre /container = 17.5 containersThe water requirement in the event at the arena of 7000 attendees is 17.5 containers.
