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Alex17521 [72]
3 years ago
15

What type of business document is used to communicate inside the company?

Computers and Technology
1 answer:
Dmitriy789 [7]3 years ago
3 0

Answer:

Where’s your answer choices

Explanation:

Put it in the comments and I’ll do the same

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Question 1. (50 points) 1.Write a program that computes information related to a sequence of entries regarding age of customers.
schepotkina [342]

Answer:

The solution code is written in Python 3:

  1. count = 0
  2. totalAge = 0
  3. group1_count = 0    #age < 10
  4. group2_count = 0    #age 10 - 20
  5. group3_count = 0    #age 20 - 40
  6. group4_count = 0    #age > 40
  7. group1_total = 0    #subtotal age <= 10
  8. group2_total = 0    #subtotal age 11 - 20  
  9. group3_total = 0    #subtotal age 21 - 40  
  10. group4_total = 0    #subtotal age > 40
  11. age = int(input("Input an age: "))
  12. youngest = age
  13. oldest = age
  14. while(age != -1):
  15.    count += 1
  16.    totalAge += age
  17.    
  18.    if(age <= 10):
  19.        group1_count += 1
  20.        group1_total += age
  21.    elif(age <= 20):
  22.        group2_count += 1
  23.        group2_total += age
  24.    elif(age <= 40):
  25.        group3_count += 1
  26.        group3_total += age
  27.    else:
  28.        group4_count += 1
  29.        group4_total += age
  30.    if(youngest > age):
  31.        youngest = age  
  32.    
  33.    if(oldest < age):
  34.        oldest = age  
  35.    age = int(input("Input an age: "))
  36.    
  37. totalCustomer = count  
  38. avgAge = totalAge / count  
  39. rangeAge = oldest - youngest  
  40. avgAgeGroup1 = group1_total / group1_count  
  41. avgAgeGroup2 = group2_total / group2_count  
  42. avgAgeGroup3 = group3_total / group3_count  
  43. avgAgeGroup4 = group4_total / group4_count  
  44. print("The total number of customers: " + str(totalCustomer))
  45. print("Total number of customer in Group 1 (<=10): " + str(group1_count))
  46. print("Total number of customer in Group 2 (11 - 20): " + str(group2_count))
  47. print("Total number of customer in Group 3 (21 - 40): " + str(group3_count))
  48. print("Total number of customer in Group 4 (> 40): " + str(group4_count))
  49. print("Average age for all customer: " + str(avgAge))
  50. print("Youngest age: " + str(youngest))
  51. print("Oldest age: " + str(oldest))
  52. print("The range of age: " + str(rangeAge))
  53. print("Average age for group 1 (<=10): " + str(avgAgeGroup1))
  54. print("Average age for group 2 (11 - 20): " + str(avgAgeGroup2))
  55. print("Average age for group 3 (21 - 40): " + str(avgAgeGroup3))
  56. print("Average age for group 4 (> 40): " + str(avgAgeGroup4))

Explanation:

Firstly, create the counter variables (e.g. count, group1_count, group2_count etc ) to track the total number of customer and number in each age group. Besides, create variables to hold the value of total of age and sub-total of each age group (Line 1 - 10). We presume there are only four age groups.

Next, prompt user to input the first age (Line 12)

Create variable youngest and oldest to track the lowest and highest age (Line 13 -14). At the moment, set the first input age as value of youngest and oldest.

Create a while loop with sentinel value  -1 (Line 16). Within the loop, track the customer occurrence by incrementing counter variables by one (Line 17, 21, 24, 27 & 30). At the same time, add the current input age to totalAge and to group total (Line 18, 22, 25, 28, & 31).

If the current youngest value is bigger than the current input age, we set the current age to youngest (Line 33- 34).

If the current oldest value is smaller than the current input age, we set the current age to oldest (Line 36- 37).

After terminating the loop with -1, calculate the average age for all customers and for each age group and the range of age (Line 42- 48)  

At last, display all the required calculation results using print function (50 - 62)

7 0
3 years ago
Write the class RoadSegmet. The class inherits from Transportation Class. The Class have a vector hourlySpeeds data field which
OLEGan [10]

Answer:

The length of time on the road segment is calculated by taking it's distance and dividing by the speed at the time of departure. This length of time is then added to the departureTime parameter to get the arrivalTime.

Define a RiverSegment class that inherits from the base TransportationClass from above. This class will have a vector<double> scheduledDepartureTimes data field that will keep track of the departure time (e.g. 10.5 represents the time 10:30) of all ferries on the river. You can assume these are sorted. Additionally, there is a _speed value that is the speed of the ferry at all times (ferries tend to be consistently slow). There is a setSpeed function to change the _speed value. Additionally, there is an addDepartureTime(double hour) function to add a departure time to the vector. Make sure the time are sorted

Computing the arrival time for the RiverSegment is a little more complicated since you need to wait for the next available departure time. Once you find the next available departure time (after the departure time passed in), you need to add the length of time on the river segment. This is done by dividing the _distance by the _speed. Add the time on the river to the departure time (from the vector of departure times) and this will give you the arrive time.

note: If there is no departure time scheduled for after your planned departure, you need to take the first available departure the following day. Our solution assumes the departure times are the same every day.

TransportationLink.h

#include <string>

using namespace std;

#ifndef __TRANSPORTATIONLINK_H__

#define __TRANSPORTATIONLINK_H__

const int HOURS_PER_DAY = 24;

const int MINS_PER_HOUR = 60;

const int MINS_PER_DAY = MINS_PER_HOUR * HOURS_PER_DAY; //24 * 60

class TransportationLink {

protected:

string _name;

double _distance;

public:

TransportationLink(const string &, double);

const string & getName() const;

double getDistance() const;

void setDistance(double);

// Passes in the departure time (as minute) and returns arrival time (as minute)

// For example:

// 8 am will be passed in as 480 (8 * 60)

// 2:30 pm will be passed in as 870 (14.5 * 60)

virtual unsigned computeArrivalTime(unsigned minute) const = 0;

};

5 0
3 years ago
write a c program to insert and delete values from stack( to perform pop and push operations) using an array data structure
Alexxx [7]

Answer:

<u>How to implement a stack in C using an array?</u>

A stack is a linear data structure that follows the Last in, First out principle (i.e. the last added elements are removed first).

This abstract data type​ can be implemented in C in multiple ways. One such way is by using an array.

​Pro of using an array:

No extra memory required to store the pointers.

Con of using an array:

The size of the stack is pre-set so it cannot increase or decrease.

3 0
3 years ago
Given an array declared to hold 100 values, the smallest index that can be used with the array is
Aneli [31]
In C influenced languages - 0.
8 0
3 years ago
Why are there so many unit testing tools? Are they efficient? Why or why not?
sineoko [7]

Answer:

 Unit testing is the software testing method in which the individual source code are associate to control data. Unit testing basically test the code to ensure that the data or information meets its design.

The aim of unit testing that each part isolate in the program and display the correct individual parts.

Unit testing tool are efficient as they provide several benefits in the development cycle. The basic efficiency of unit testing tools depend upon its type of testing. Unit testing basically validate the units of source code in the program.

For example: when the loop and function in the program work efficiently.

5 0
3 years ago
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