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RoseWind [281]
3 years ago
15

Three noise sources produce volume (loudness) levels of 70, 73, and 80 dB when acting separately. When the sources act together,

the resultant intensity is the sum of the individual intensities. Find the sound volume level in decibels when the three sources act at the same time.
Physics
1 answer:
Mashutka [201]3 years ago
8 0

Sound at 70 dB is 70 dB louder than the human reference level.  That's 10⁷ times as much as the reference sound power.

Sound at 73 dB is 73 dB louder than the human reference level.  That's 10⁷.³  or  2 x 10⁷  times as much as the reference sound power.

Sound at 80 dB is 80 dB louder than the human reference level.  That's 10⁸  or 10 x 10⁷ times as much as the reference sound power.

Now we can adumup:

Intensity of all 3 sources = (10⁷) + (2 x 10⁷) + (10 x 10⁷)

Intensity = (13 x 10⁷) times the sound power reference intensity.

Intensity in dB = 10 log (13 x 10⁷) = 10 (7 + log(13)

Intensity = 70 + 10 log(13)

Intensity = 70 + 10 (1.114)

Intensity = 70 + 11.14

Intensity = <em>81.14 dB</em>

<em>______________________________________</em>

Looking at the questioner's profile, I seriously wonder whether I'll ever get a comment in return from this creature, and how I'll ever find out if my solution is correct.  For that matter, I'm also seriously questioning how and whether my solution will ever be used for anything.

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Answer:

B = 4.059 x 10¹⁵ T

Explanation:

Given,

Number of loop, N = 400

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Current, I = 1.05 x 10⁴ A

Magnetic field at the center of the loop

B = \dfrac{\mu_0NI}{2R}

B = \dfrac{4\pi\times 10^{-7}\times 400 \times 1.05 \times 10^4}{2\times 0.65\times 10^{-15}}

B = 4.059 x 10¹⁵ T

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A rabbit runs 28 m toward the left in 9 s; then the rabbit suddenly changes direction and runs 18 m toward the right in the next
Viefleur [7K]

Answer:

The answer is 3.111111.

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3 years ago
Please help!!! Which is a heterogeneous mixture?
katrin [286]

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pizza is a heterogeneous mixture.

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Two parallel wires carry currents in the same direction. If the currents in the wires are 1A and 4A and the wires are 5 m apart.
serious [3.7K]

Answer:

1.6\times 10^{-7} N

2.4\times 10^{-7} N

Explanation:

i_{1} = 1 A

i_{2} = 4 A

r = distance between the two wire = 5 m

F = Force per unit length acting between the two wires

Force per unit length acting between the two wires is given as

F = \frac{\mu _{o}}{4\pi }\frac{2i_{1}i_{2}}{r}

F = (10^{-7})\frac{2(1)(4)}{5}

F = 1.6\times 10^{-7} N

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Magnetic field midway between the two wires is given as

B = \frac{\mu _{o}}{4\pi } \left \left ( \frac{2i_{2}}{r'} \right - \frac{2i_{1}}{r'} \right \right ))

B = (10^{-7}) \left \left ( \frac{2(4)}{2.5} \right - \frac{2(1)}{2.5} \right \right ))

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5 0
3 years ago
(i) Calculate the energy, in electron volts, of a photon whose frequency is (a) 620 THz}, (b) 3.10GHz , and(c) 46.0 MHz
DedPeter [7]

The energy in electron volts of the photons that has the following frequencies is as follows:

  1. 620 THz = 2.564eV
  2. 3.10GHz = 1.28 × 10-⁵eV
  3. 46.0 MHz = 1.902 × 10-⁷eV

<h3>How to calculate energy?</h3>

The energy of a photon can be calculated using the following formula:

E = hf

Where;

  • E = energy
  • h = Planck's constant (6.626 × 10-³⁴ J/s)
  • f = frequency

First, we convert the frequencies to hertz as follows;

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  • 3.10GHz = 3.1 × 10⁹Hz
  • 46.0MHz = 4.6 × 10⁷Hz

  1. E = 6.626 × 10-³⁴ × 6.2 × 10¹⁴ = 2.564eV
  2. E = 6.626 × 10-³⁴ × 3.1 × 10⁹ = 1.28 × 10-⁵eV
  3. E = 6.626 × 10-³⁴ × 4.6 × 10⁷ = 1.902 × 10-⁷eV

Learn more about energy of a photon at: brainly.com/question/2393994

#SPJ1

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