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Aleks [24]
3 years ago
7

The blades of a fan running at low speed turn at 26.2 rad/s. When the fan is switched to high speed, the rotation rate increases

uniformly to 36.5 rad/s in 5.75 seconds. What is the magnitude of the fan's angular acceleration
Physics
2 answers:
Lady bird [3.3K]3 years ago
8 0

Answer: 1.79\ rad/s^2

Explanation:

Given

Initial angular speed is \omega_1=26.2\ rad/s

Final angular speed is \omega_2=36.5\ rad/s

Time period t=5.75\ s

Magnitude of the fan's acceleration is given by

\Rightarrow \alpha=\dfrac{\omega_2-\omega_1}{t}

Insert the values

\Rightarrow \alpha=\dfrac{36.5-26.2}{5.75}\\\\\Rightarrow \alpha=\dfrac{10.3}{5.75}\\\\\Rightarrow \alpha=1.79\ rad/s^2

Thus, fan angular acceleration is 1.79\ rad/s^2

valina [46]3 years ago
8 0

Answer:

The angular acceleration is given by 1.8 rad/s^2.

Explanation:

initial angular speed, wo = 26.2 rad/s

final angular velocity, w = 36.5 rad/s

time, t = 5.75 seconds

The first equation of motion is

w = wo + \alpha t\\\\36.5 = 26.2 + 5.75\alpha\\\\\alpha =  1.8 rad/s^2

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Given that a plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again.

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