3:80
4:20 those are the answers
Answer:
in fraction from it is 
Step-by-step explanation:
Answer:
the confidence interval for the true weight of the specimen is;
4.1593 ≤ μ ≤ 4.1611
Step-by-step explanation:
We are given;
Standard deviation; σ = 0.001
Sample size; n = 8
Average weight; x¯ = 4.1602
We are given a 99% confidence interval and the z-value at this interval is 2.576
Formula for confidence interval is;
CI = x¯ ± (zσ/√n)
Plugging in the relevant values, we have;
CI = 4.1602 ± (2.576 × 0.001/√8)
CI = 4.1602 ± 0.000911
CI = (4.1602 - 0.000911), (4.1602 + 0.000911)
CI ≈ (4.1593, 4.1611)
Thus, the confidence interval for the true weight will be expressed as;
4.1593 ≤ μ ≤ 4.1611
Where μ represents the true weight
Answer:
here's the solution : -
=》2x - 3y = -29
=》x + 6y = 23
=》x = 23 - 6y
now, plugging the value of x in equation 1, we get : -
=》2x - 3y = -29
=》2 (23 - 6y) - 3y = - 29
=》46 - 12y - 3y = -29
=》-15y = -29 - 46
=》y = -75 ÷ -15
=》y = 5
now, plugging the value of y as 5 in equation 2
=》x + 6y = 23
=》x + (6 × 5.2) = 23
=》x = 23 - 30
=》x = - 7
