2 years ago

Help me with this please

Mathematics

1 answer:

ch4aika [34]2 years ago

5 0

Answer:

have an F- on math call for help!

Step-by-step explanation:

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The required equation is $y=-\frac{1}{3}x+2$ .

Step-by-step explanation:

The equation of line cd is

$y=3x-3$

Slope intercept form of a line is

$y=mx+b$

Where, m is slope and b is y-intercept.

Slope of line cd is 3.

The product of slopes of two perpendicular lines is -1.

$m_1\times m_2=-1$

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$m_2=-\frac{1}{3}$

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Point slope form of a line is

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Slope of perpendicular line is $-\frac{1}{3}$ and line passing through the point (3,1).

$y-1=-\frac{1}{3}(x-3)$

$y=-\frac{1}{3}x+1+1$

$y=-\frac{1}{3}x+2$

Therefore the required equation is $y=-\frac{1}{3}x+2$ .

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Help me with this please​

Help me with this please