The sum of two numbers is 56. Seven times the smaller number is 12 more than three times the larger number. Find the numbers.
2 answers:
Answer:
x = 18
y = 38
Step-by-step explanation:
Let the smaller number be = x
Let the larger number be = y
Sum of the number, x + y = 56 --------- ( 1 )
Seven times smaller number = 7x
Three times larger number = 3y
Seven times smaller = 12 more than 3times larger , 7x = 12 + 3y ----- ( 2 )
Solve ( 1 ) and ( 2 )
x + y = 56 => x = 56 - y
Substitute x in ( 2 )
7x - 3y = 12
7(56 - y) - 3y = 12
392 - 7y - 3y = 12
-10y = 12 - 392
-10y = - 380
y = 38
Substitute y in ( 1 )
x + y = 56
x + 38 = 56
x = 56 - 38
x = 18
X+y=56
7x-12=3y
7x-3y=12
3x+3y=168
7x-3y=12
10x=180
X=18
56-18=y
Y=38
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