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GarryVolchara [31]
3 years ago
5

4) A jellybeans machine contains 25 green jellybeans, 57 red jellybeans, 31

Mathematics
1 answer:
stiv31 [10]3 years ago
6 0
The answer is 12.5 because if you add them all together you get 200 and 25 of 200% is 12.5.
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Someone help!! Thanks
Andru [333]

Answer:

I believe it is 21

Step-by-step explanation:

4 0
3 years ago
Find the table with unit rates greater than the unit range in the graph. Then arrange these tables in order from least to greate
Lubov Fominskaja [6]

Answer:

Except table 2, all tables have greater unit rate than the graph.

The required arrangements of tables is  

Table 2 < Table 1 < Table 3 < Table 5 < Table 4 < table 7 < Table 6

Step-by-step explanation:

Formula for unit rate :

m=\dfrac{y_2-y_1}{x_2-x_1}

From the given graph it is clear that the line passes through the points (0,0) and (11,20). So, unit rat of graph is

m=\dfrac{20-0}{11-0}=1.8181...

Similarly, we need to calculate the unit rate for each table.

m_1=\dfrac{26-13}{14-7}=\dfrac{13}{7}=1.85714

m_2=\dfrac{18-9}{10-5}=\dfrac{9}{5}=1.8

m_3=\dfrac{34-17}{18-9}=\dfrac{17}{9}=1.88..

m_4=\dfrac{42-21}{22-11}=\dfrac{21}{11}=1.9090..

m_5=\dfrac{38-19}{20-10}=\dfrac{19}{10}=1.9

m_6=\dfrac{50-25}{26-13}=\dfrac{25}{13}=1.923

m_7=\dfrac{46-23}{24-12}=\dfrac{23}{12}=1.9166..

Except table 2, all tables have greater unit rate than the graph.

The required arrangement of tables is  

Table 2 < Table 1 < Table 3 < Table 5 < Table 4 < Table 7 < Table 6

4 0
3 years ago
Why is t^2+4z^2 prime
erma4kov [3.2K]
A polynomial is considered prime if it cannot be factored into the standard linear form, that problem cannot be factored, making it prime
7 0
4 years ago
Describe the solutions for the quadratic equation shown below:
PtichkaEL [24]

The solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots

To determine the the type of roots the quadratic equation 9x² - 6x + 5 = 0, we use the quadratic formula to find the roots.

So, for a quadratic equation ax + bx + c = 0, the roots are

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

With a = 9, b = -6 and c = 5, the roots of our equation are

x = \frac{-(-6) +/- \sqrt{(-6)^{2} - 4 X 9 X 5} }{2 X 9} \\x = \frac{6 +/- \sqrt{36 - 180} }{18} \\x = \frac{6 +/- \sqrt{-144} }{18} \\x = \frac{6 +/- \sqrt{-12} }{18}\\x = \frac{6}{18} +/- i\frac{12}{18} \\x = \frac{1}{3} +/- i\frac{2}{3} \\x = \frac{1 + 2i}{3}  or \frac{1 - 2i}{3}

Since the roots of the equation are (1 + 2i)/3 and (1 - 2i)/3, there are 2 complex roots.

So, the solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots

Learn more about quadratic equations here:

brainly.com/question/18117039

5 0
3 years ago
Please help I don't understand ​
DIA [1.3K]

Answer:

14/18

Step-by-step explanation:

7/9 x 2= 14/18

7/9=14/18

but not sure what proportion means but just look up definition and yeah

I hope this was helpful!

5 0
3 years ago
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