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3 years ago

What happens when plates diverge?

Chemistry

2 answers:

erastova [34]3 years ago

7 0

Answer:

what kind of plates?

Explanation:

you didn't put enough info

TEA [102]3 years ago

7 0

Answer:

Diverge means when the plates go in diffrent directions

Explanation:

A divergent boundary occurs when two tectonic plates move away from each other. Along these boundaries, earthquakes are common and magma (molten rock) rises from the Earth's mantle to the surface, solidifying to create new oceanic crust.

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1. Lab Investigator: Chemical Reactions cannot be used for

Elina [12.6K]

1: viewing any chemical reaction in a laboratory

2: dangerous to look at when it burns & used in photography, fireworks, and flares

3: the product

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3 years ago

Read 2 more answers

Compare the density of 25g of copper to 80g of copper?

tiny-mole [99]

Answer:

Explanation:

25g is less dense than 80g therefore will mostly float. if you subtract 80-25 that will leave you will 55 as the difference

7 0

3 years ago

Identify each statement as true or false. Explain in every case.a.Ionization energies are always negative quantities.b.Oxygen ha

worty [1.4K]

Answer:

(a) FALSE

(b) FALSE

(d) FALSE

Explanation:

Ionization energy refers to the energy needed for removal of a valence electron present in valence shell of a gaseous atom.

(a) The value of ionization energy of an atom is always positive. This is because energy has to be always supplied or provided to a gaseous atom for the removal of the valence electron.

Therefore, the statement (A) is false

(b) The ionization energy of an atom increases across a period i.e. from left to right. This is because the effective nuclear charge that is experienced by the valence electron increases from left to right in the periodic table, as the atomic number increases.

So, more energy is required to remove the valence electron of fluorine as compared to oxygen.

Therefore, the ionization energy of fluorine is greater than oxygen.

Therefore, the statement (B) is false

(c) First ionization energy is energy needed for removal of first electron present in valence shell of a neutral atom. Whereas, second ionization energy is the energy needed for removal of second electron present in valence shell of a monovalent cation

The second ionization energy of an atom is always greater than the first ionization energy. This is because removing an electron from a positively charged species, requires more energy.

Therefore, the statement (C) is true

(d) The third ionization energy refers to the energy needed to remove the third electron from a divalent cation.

Therefore, the statement (D) is false

7 0

3 years ago

Be sure to answer all parts. The standard enthalpy of formation and the standard entropy of gaseous benzene are 82.93 kJ/mol and

skelet666 [1.2K]

Answer : The values of $\Delta H^o,\Delta S^o\text{ and }\Delta G^o$ are $33.89kJ,95.94J/K\text{ and }5.299kJ/mol$ respectively.

Explanation :

The given balanced chemical reaction is,

$C_6H_6(l)\rightarrow C_6H_6(g)$

First we have to calculate the enthalpy of reaction $(\Delta H^o)$ .

$\Delta H^o=H_f_{product}-H_f_{reactant}$

$\Delta H^o=[n_{C_6H_6(g)}\times \Delta H_f^0_{(C_6H_6(g))}]-[n_{C_6H_6(l)}\times \Delta H_f^0_{(C_6H_6(l))}]$

where,

$\Delta H^o$ = enthalpy of reaction = ?

n = number of moles

$\Delta H_f^0_{(C_6H_6(g))}$ = standard enthalpy of formation of gaseous benzene = 82.93 kJ/mol

$\Delta H_f^0_{(C_6H_6(l))}$ = standard enthalpy of formation of liquid benzene = 49.04 kJ/mol

Now put all the given values in this expression, we get:

$\Delta H^o=[1mole\times (82.93kJ/mol)]-[1mole\times (49.04J/mol)]$

$\Delta H^o=33.89kJ/mol=33890J/mol$

Now we have to calculate the entropy of reaction $(\Delta S^o)$ .

$\Delta S^o=S_f_{product}-S_f_{reactant}$

$\Delta S^o=[n_{C_6H_6(g)}\times \Delta S^0_{(C_6H_6(g))}]-[n_{C_6H_6(l)}\times \Delta S^0_{(C_6H_6(l))}]$

where,

$\Delta S^o$ = entropy of reaction = ?

n = number of moles

$\Delta S^0_{(C_6H_6(g))}$ = standard entropy of formation of gaseous benzene = 269.2 J/K.mol

$\Delta S^0_{(C_6H_6(l))}$ = standard entropy of formation of liquid benzene = 173.26 J/K.mol

Now put all the given values in this expression, we get:

$\Delta S^o=[1mole\times (269.2J/K.mol)]-[1mole\times (173.26J/K.mol)]$

$\Delta S^o=95.94J/K.mol$

Now we have to calculate the Gibbs free energy of reaction $(\Delta G^o)$ .

As we know that,

$\Delta G^o=\Delta H^o-T\Delta S^o$

At room temperature, the temperature is $25^oC\text{ or }298K$ .

$\Delta G^o=(33890J)-(298K\times 95.94J/K)$

$\Delta G^o=5299.88J/mol=5.299kJ/mol$

Therefore, the values of $\Delta H^o,\Delta S^o\text{ and }\Delta G^o$ are $33.89kJ,95.94J/K\text{ and }5.299kJ/mol$ respectively.

6 0

3 years ago

Read 2 more answers

How many molecules are in 79g of fe2o3

horrorfan [7]

Convert grams —> mols and then mols —> atoms

We know that there are 6.02 x 10^23 atoms/mol

And we know that there are about 160 grams of fe2o3 per mol

So (79g fe2o3)/(160 g/mol) = .49 mol fe2o3

Now we use avogadro’s number to do

(.49 mol fe2o3)/(6.02 x 10^23 atoms/mol) = the answer.

I’ll leave the easy math to you.

7 0

3 years ago