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Elena L [17]
2 years ago
15

Was Velcro a mistake or purpose

Chemistry
1 answer:
Vera_Pavlovna [14]2 years ago
6 0

Answer:

Velcro was an accident.

Explanation:

hope it helps

sry if im wrong

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I need help with this question its not hard at all im just not sure
Lena [83]

Answer:

It is the third one, 2 atoms of Aluminum and 3 atoms of Oxygen

7 0
3 years ago
16 Which change results in the formation of different substances?(1) burning of propane
Trava [24]
1. The burning of propane creates different substances: propane and oxygen combine to create water and carbon dioxide:

<span><span>C<span>3</span>H<span>8</span></span> + 5 <span>O<span>2</span></span> becomes 3 CO2 + 4 <span>H<span>2</span>O</span> + heat
</span><span>
2. When NaCl melts, it is changing state, but it is still the same NaCl.

3. When gaseous CO2 deposits it is changing state, but it is still the same CO2.

4. When (presumably liquid) water solidifies, it is changing state, but it is still the same water.

So the answer is 1.</span>
6 0
4 years ago
Read 2 more answers
Select the structure that corresponds
Lostsunrise [7]

Answer:

C. both

Explanation:

8 0
2 years ago
CuSO4.5H2O(k) ısı CuSO4(k) + 5 H2O(g) eşitliğine göre bakır sülfatın kristal suyu miktarı ve kaba formülü hesaplanacaktır.
baherus [9]

Answer:

159.609 g/mol

Explanation:

According to the CuSO4.5H2O (k) heat CuSO4 (k) + 5 H2O (g) equation, the crystal water amount of copper sulfate and its rough formula will be calculated.

Weight of copper sulfate containing crystal water = m1 = 249.62… g

Weight of copper sulfate without crystal water weighed = m2 = 159.62 g

Accordingly, calculate the x and y values ​​in the molecular formula of copper sulfate (xCuSO4.yH2O).

3 0
3 years ago
Benzophenone has a normal freezing point of +48.1 oC, with freezing point depression constant Kfpt = − 9.78 oC/m. A 0.1500 molal
Neporo4naja [7]

Answer:

i = 2.79

Explanation:

The excersise talks about the colligative property, freezing point depression.

Formula to calculate the freezing point of a solution is:

Freezing point of pure solvent - Freezing point of solution = m . Kf . i

Let's replace data given. (i = Van't Hoff factor, numbers of ions dissolved in solution)

48.1°C - 44°C = 0.15 m . 9.78°C/m . i

4.1°C / (0.15 m . 9.78°C/m) = i

i = 2.79

In this case, numbers of ions dissolved can decrease the freezing point of a solution, which is always lower than pure solvent.

3 0
3 years ago
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