2 years ago

What is the equation of the line graphed below?

1 answer:

dexar [7]2 years ago

4 0

Answer: y = -3x this is the answer.

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leonid [27]

6 and 11 and 3 and 22.
The order of the diagram may look different however, the prime factors are the same.

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3 years ago

umka2103 [35]

Answer:

hmmmmmm Okay From what question?

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3 years ago

topjm [15]

Answer:

B. 5,7,12 is what I got.

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3 years ago

ivanzaharov [21]

3 is the correct answer I believe

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2 years ago

Paul [167]

Answer:

The total distance traveled by spaceship in all is 5 / 6 of a Light Year

Step-by-step explanation:

Here, the distance traveled by spaceship in first go = 3/ 4 Light Year

The distance traveled after stopping at space station = 1/ 12 Light Year

Now, the Total distance traveled by Spaceship = Sum of all distances traveled by spaceship

= $(\frac{3}{4} ) + (\frac{1}{12} )$

= $\frac{3(3) + 1}{12} = \frac{9 + 1}{12} = \frac{10}{12} = \frac{5}{6} \\\implies (\frac{3}{4} ) + (\frac{1}{12} ) = \frac{5}{6}$

or,<u> 3/ 4 Light Year + 1/ 12 Light Year = 5 / 6 of a Light Year</u>

Hence, the total distance traveled by spaceship in all is 5 / 6 of a Light Year

6 0

3 years ago