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2 years ago

Which set of side length is a Pythagorean triple? A. 2,3,13 b. 5,7,12 C. 10, 24, 29 D. 11,60,61

Mathematics

2 answers:

lara31 [8.8K]2 years ago

6 0

I’m pretty sure the answer is B

topjm [15]2 years ago

5 0

Answer:

B. 5,7,12 is what I got.

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(2a)(2b) please help

DENIUS [597]

The answer is 2^a+b lol

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2 years ago

Show the expression as the base to one power.

coldgirl [10]

Step-by-step explanation:

${4}^{5}. {4}^{3 } = {4}^{5 + 3} = {4}^{8}$

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2 years ago

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Vesna [10]

Answer:

Angles

Step-by-step explanation:

A polygon is a shape, I don't think there are conversions since a polygon is not something you can measure. A population can be counted with normal numbers, 1,2,3... density is calculated with mass and volume, not radians and degrees.... yeah.

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5 0

1 year ago

Read 2 more answers

A rectangle in the xy-coordinate plane is formed by the points (1,−4), (1,6), (3,−4), and (3,6). What is the perimeter of this r

Airida [17]

Answer:

Perimeter of the rectangle= $20+2\sqrt{104}$

Step-by-step explanation:

The perimeter of the rectangle with the given coordinates is the sum of its all four sides:

Let the points be A(1,-4), B(1,6), C(3,-4) and D(3,6)

Finding the sides of the rectangle using the Distance formula:

AB=

$\sqrt{(1-1)^2+(6-(-4))^2} \\\\=\sqrt{0+10^2} \\\\=\sqrt{100}\\\\ =10$

$=\sqrt{(3-1)^2+(-4-6)^2} \\\\=\sqrt{2^2+(-10)^2}\\\\ =\sqrt{4+100} \\\\=\sqrt{104}$

CD=

$\sqrt{(3-3)^2+(6-(-4))^2} \\\\=\sqrt{0+10^2} \\\\=\sqrt{100} \\\\=10$

AD=

$\sqrt{(3-1)^2+(6-(-4))^2} \\\\=\sqrt{2^2+10^2} \\\\=\sqrt{4+100}\\\\ =\sqrt{104}$

Perimeter of the rectangle=AB+BC+CD+AD

= $10+\sqrt{104}+ 10+\sqrt{104}$

Perimeter of the rectangle= $20+2\sqrt{104}$

7 0

3 years ago

Simplify 6 - 2³ + (-9 + 5) · 2.

oksian1 [2.3K]

Answer: your answer is -10

Step-by-step explanation:j

if you dont believe me check your answer on a math website

8 0

2 years ago

Read 2 more answers