All categories

1 year ago

R+(−5r) does any one know yhe answer to this if es let me know thx=thank you

Mathematics

1 answer:

Lyrx [107]1 year ago

5 0

Answer: -4

Step-by-step explanation:

Combine r and −5r to get −4r.

dr/d (−4r)

The derivative of nax

is nax n−1 .

−4r 1−1

Subtract 1 from 1.

−4r0

For any term t except 0, t0

=1.

−4

You might be interested in

Mr. Bulky’s Candy Emporium sells all candy items for $0.60 per ounce. Penny and Ruth each bought several different types of cand

exis [7]

Answer: what’s the rest of the question? You didn’t provide enough data…✨

Step-by-step explanation:

4 0

2 years ago

Please help i beg i never get these right

Anuta_ua [19.1K]

Answer:

$\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}$

Step-by-step explanation:

Given

$\sin(105^o)$

Required

Solve

Using sine rule, we have:

$\sin(A + B) = \sin(A)\cos(B) + \sin(B)\cos(A)$

This gives:

$\sin(105^o) = \sin(60 + 45)$

So, we have:

$\sin(60 + 45) = \sin(60)\cos(45) + \sin(45)\cos(60)$

In radical forms, we have:

$\sin(60 + 45) = \frac{\sqrt 3}{2} * \frac{\sqrt 2}{2} + \frac{\sqrt 2}{2} * \frac{1}{2}$

$\sin(60 + 45) = \frac{\sqrt 6}{4} + \frac{\sqrt 2}{4}$

Take LCM

$\sin(60 + 45) = \frac{\sqrt 6 + \sqrt 2}{4}$

Rewrite as:

$\sin(60 + 45) = \frac{\sqrt 2 + \sqrt 6}{4}$

Hence:

$\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}$

3 0

2 years ago

What is the slope of the<br> line that passes through the<br> points (-12, -5) and (0, -8)?

denis-greek [22]

Answer:

I think its - 2/3

Step-by-step explanation:

5 0

3 years ago

Could somebody help me on the 2 question please

ozzi

-20 because after the the thermometer hits zero the more negative the temperature gets the colder it is

8 0

3 years ago

Read 2 more answers

1 of 3

lara31 [8.8K]

Answer:

−

Step-by-step explanation:

hope this helps

3 0

3 years ago