If the three vertices of the rhombus are W(2,5),x(6,3),Y(2,1) then the area of the rhombus is 16 square units.
Given the three vertices of the rhombus are W(2,5),x(6,3),Y(2,1).
We are required to find the area of the rhombus when the fourth point Z is plotted.
We have to plot the points of the rhombus in the graph. We know that all the sides of the rhombus should be equal to each other. So by adjusting the blocks in the graph we will be able to plot Z as (-2,3).
In this way the diagonals are ZX and WY.
ZX=
=
=8 units
WY=
=
=4 units
Area of rhombus=1/2 *(
)
=1/2* (8*4)
=8*2
=16 Square units.
Hence if the three vertices of the rhombus are W(2,5),x(6,3),Y(2,1) then the area of the rhombus is 16 square units.
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Answer:
One equation would be y= -1.5x +11
Step-by-step explanation:
Here's a table to show the coordinates
x: y:
8 -1
-------------------
-4 17
the x coor. 8 goes down by 12 to get to the next x coor. -4.
8-12= -4
the y coor. -1 goes up by 18 to get to the next y coor. 17.
-1+18= 17
therefore 18/-12 is -1.5 which can be your k in y=kx+b.
Check your answer.
-1.5*8= -12 but when you add 11, you get the y coor. -1
Do the same with the other x coor.
-4*-1.5= 6 + 11 =17
11 can be your b in the slope-intercept form equation.
One equation may be y = -1.5x +11
Answer:
(2,5)) ,(-2,-3),(8,2),(4,-6)
Step-by-step explanation:
it is rotated by 180 degree so evrything becomes positve beside the -6