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spin [16.1K]
3 years ago
8

Suppose speeds of vehicles traveling on a highway have an unknown distribution with mean 63 and standard deviation 4 miles per h

our. A sample of size n-44 is randomly taken from the population and the mean is taken. Using the Central Limit Theorem for Means, what is the standard deviation for the sample mean distribution?
Mathematics
1 answer:
Mashutka [201]3 years ago
6 0

Answer:

The standard deviation for the sample mean distribution=0.603

Step-by-step explanation:

We are given that

Mean,\mu=63

Standard deviation,\sigma=4

n=44

We have to find the standard deviation for the sample mean distribution using  Central Limit Theorem for Means.

Standard deviation for the sample mean distribution

\sigma_x=\frac{\sigma}{\sqrt{n}}

Using the formula

\sigma_x=\frac{4}{\sqrt{44}}

\sigma_x=\frac{4}{\sqrt{2\times 2\times 11}}

\sigma_x=\frac{4}{2\sqrt{11}}

\sigma_x=\frac{2}{\sqrt{11}}

\sigma_x=0.603

Hence, the standard deviation for the sample mean distribution=0.603

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Answer:

0.12 ± 1.96 * √(0.12(0.88) / 100)

Step-by-step explanation:

Confidence interval :

Phat ± Zcritical * √(phat(1 -phat) / n)

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3 years ago
A right triangle has side lengths AC = 7 inches, BC = 24
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Therefore, the measures of the angles in triangle ABC is as follows:

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<h3>How to find angles of right triangle?</h3>

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Using trigonometric ratios,

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