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Alexus [3.1K]
3 years ago
11

Write and balance the following equation:

Chemistry
1 answer:
Degger [83]3 years ago
3 0

Balanced equation :

3NaOH + Fe(NO₃)₃⇒ Fe(OH)₃ +  3NaNO₃

<h3>Further explanation</h3>

Given

Word equation

Required

Balanced equation

Solution

Chemical equations can be expressed in terms of:

  • word equation
  • skeleton equation
  • balanced equation

Sodium hydroxide reacts with a solution of iron (III)

nitrate to create a solid of iron (III) hydroxide in a solution of

sodium nitrate.

We determine the chemical formula of each compound then we balance the chemical equation

Sodium hydroxide = NaOH

Iron (III)nitrate = Fe(NO₃)₃

Iron (III) hydroxide = Fe(OH)₃

Sodium nitrate = NaNO₃

Reaction

NaOH + Fe(NO₃)₃⇒ Fe(OH)₃ +  NaNO₃

Give a coefficient(most complex compound = 1)

aNaOH + Fe(NO₃)₃⇒ bFe(OH)₃ +  cNaNO₃

Fe, left = 1, right=b⇒b=1

N, left=3, right=c⇒c=3

O, left=a+9, right=3b+3c⇒a+9=3b+3c⇒a+9=3.1+3.3⇒a+9=12⇒a=3

The equation becomes :

<em>3NaOH + Fe(NO₃)₃⇒ Fe(OH)₃ +  3NaNO₃</em>

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Answer:

It decreases.

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The student placed 10 mL of PbCl2 (saturated solution) in the test tube and added a pinch of lead acetate. When the test tube wa
STALIN [3.7K]
PbCl₂(s) ⇄ Pb²⁺(aq) + 2Cl⁻(aq)

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4 0
3 years ago
Which is least likely to be reduced? <br> A. Zn^2+ <br> B. Fe^3+ <br> C. Cu^2+ <br> D. Fe^2+
alekssr [168]

A. Zn²⁺

<h3>Further explanation</h3>

Given

Cations of several elements

Required

The least to be reduced

Solution

If we look at the voltaic series:

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe²⁺-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Fe³⁺-Ag-Pt-Au </em>

The electrode which is easier to reduce than the hydrogen (H2) electrode has a positive sign (E red= +) and is located to the right of the voltaic series (right of H)

The electrode which is easier to oxidize than the hydrogen (H2) electrode and is difficult to experience reduction has a negative sign (E red= -) and is located to the left of the voltaic series (left of H)

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6 0
3 years ago
What is the temperature (°C) of 1.75 g of O2 gas occupying 4.60 L at 1.00 atm?
julsineya [31]

Given- m= 1.75 g  

Now moles of O2 gas= Mass/ Molar mass  

n = 1.75/32  

V= 2L  

P= 1atm  

R=0.0821.....Constant  

As PV=nRT  

=> T=PV/nR  

= 1* 2/ (1.75/32)*0.0821 K  

= 2*32/1.75* 0.0821 K  

= 445.45 K  

= (445.45- 273.15) degrees celsius  

= 172.30 degrees celsius..... ANSWER

4 0
3 years ago
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