Answer:
<u>The Standard enthalpy of reaction:</u>
Explanation:
Given- Standard Heat of Formation:
= -3110 kJ/mol,
= -286 kJ/mol,
= -1279 kJ/mol
<u><em>Given chemical reaction:</em></u> P₄O₁₀(s) + 6H₂O → 4H₃PO₄
<em>The standard enthalpy of reaction:</em> = ?
<u><em>To calculate the Standard enthalpy of reaction</em></u> (), <u><em>we use the equation:</em></u>
<u>Therefore, the Standard enthalpy of reaction:</u>
D. It is the heat required to change a gram of substance from a liquid to a gas.
Explanation:
The heat of vaporization is the heat required to change a gram of substance from a liquid to a gas.
- It is also known as the enthalpy of vaporization.
- The heat of vaporization is the quantity of heat needed to change one gram of a substance from liquid to gas.
- This heat of vaporization is dependent on the pressure conditions the process is taking place.
- Different liquids have their heat of vaporization.
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The answer is excess reactant
C is the correct answer since it outputs and inputs chemicals