The most important reaction involved in the reoxidation of NADH is Pyruvate → lactate
Two ATP were generated as a net result of glycolysis, two NAD+ were converted to two NADH + H+, and two glucose molecules were divided into two pyruvate molecules.
Pyruvate will go through a process called fermentation when oxygen is absent.
The NADH + H+ from glycolysis will be recycled back to NAD+ during fermentation, allowing glycolysis to proceed.
NAD+ is converted during the glycolysis process into NADH + H+.
Glycolysis cannot proceed without the presence of NAD+.
The NADH produced during glycolysis will be oxidised to create new NAD+ during aerobic respiration, when it will be used once more in glycolysis.
Pyruvate will undergo oxidation in the absence of oxygen or if an organism is unable to engage in aerobic respiration.
Hence The most important reaction involved in the reoxidation of NADH is Pyruvate → lactate
Learn more about Reoxidation here
brainly.com/question/14853085
#SPJ4
Answer:
Neon is a chemical element with the symbol Ne and atomic number 10. It is a noble gas.
Not sure why you reposted your question, the answer is D as explained in my other answer.
<h3>Answer:</h3>
221.90 g.mol⁻¹
<h3>Explanation:</h3>
The mass of contained by a molecule is known as molecular mass. It is the sum of atomic weights of the elements contained by the molecule. In given case Iodine Pentafluoride has a chemical formula,
IF₅
The atomic weights of each element are as;
Iodine = 126.90 g.mol⁻¹
Fluorine = 19.00 g.mol⁻¹
As there are five atoms of Fluorine so, we will multiply the atomic weight of Fluorine by five and that of Iodine by one as there is only one Iodine atom.
Therefore,
Molecular Mass of IF₅ = (1 × 126.90 g.mol⁻¹) + (5 × 19.00 g.mol⁻¹)
Molecular Mass of IF₅ = (126.90 g.mol⁻¹) + (95.00 g.mol⁻¹)
Molecular Mass of IF₅ = 221.90 g.mol⁻¹
Answer:
I hoped it helps you fod blessed:)