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Otrada [13]
3 years ago
12

Iodine pentafluoride reacts slowly with glass and violently with water. determine its molecular mass.

Chemistry
1 answer:
pickupchik [31]3 years ago
8 0
<h3>Answer:</h3>

               221.90 g.mol⁻¹

<h3>Explanation:</h3>

                          The mass of contained by a molecule is known as molecular mass. It is the sum of atomic weights of the elements contained by the molecule. In given case Iodine Pentafluoride has a chemical formula,

                                                          IF₅

The atomic weights of each element are as;

                                        Iodine  =  126.90 g.mol⁻¹

                                        Fluorine  =  19.00 g.mol⁻¹

As there are five atoms of Fluorine so, we will multiply the atomic weight of Fluorine by five and that of Iodine by one as there is only one Iodine atom.

Therefore,

         Molecular Mass of IF₅  =  (1 × 126.90 g.mol⁻¹) + (5 × 19.00 g.mol⁻¹)

         Molecular Mass of IF₅  =  (126.90 g.mol⁻¹) + (95.00 g.mol⁻¹)

         Molecular Mass of IF₅  =  221.90 g.mol⁻¹

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Give the percent yield when 162.8 g of CO2 are formed from the reaction of excess amount of
Zepler [3.9K]

Answer:

84.86%

Explanation:

Step 1:

We'll begin by writing a balanced equation for the reaction between C8H18 and O2 to produce CO2. This is illustrated below:

2C8H18 + 25O2 —> 16CO2 + 18H2O

Step 2:

Now, let us calculate the mass of O2 that reacted and the mass of CO2 produced from the balanced equation above. This is illustrated below:

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 25 x 32 = 800g

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the balanced equation = 16 x 44 = 704g

Therefore the mass of O2 that reacted from the balanced equation is 800g

The mass of CO2 produced from the balanced equation is 704g

Step 3:

Determination of the theoretical yield of CO2. This is illustrated below:

From the balanced equation above,

800g of O2 reacted to produced 704g of CO2.

Therefore, 218g of O2 will react to produce = (218 x 704)/800 = 191.84g of CO2.

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Step 4:

Determination of the percentage yield of CO2. This is illustrated below:

Actual yield = 162.8g

Theoretical yield = 191.84g

Percentage yield =?

Percentage yield = Actual yieldm/Theoretical yield x100

Percentage yield = 162.8/191.84 x100

Percentage yield = 84.86%

Therefore, the percentage yield of CO2 is 84.86%

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Answer:

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Explanation:

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Answer:

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