Iodine pentafluoride reacts slowly with glass and violently with water. determine its molecular mass.

Chemistry

1 answer:

pickupchik [31]3 years ago

8 0

<h3>Answer:</h3>

221.90 g.mol⁻¹

<h3>Explanation:</h3>

The mass of contained by a molecule is known as molecular mass. It is the sum of atomic weights of the elements contained by the molecule. In given case Iodine Pentafluoride has a chemical formula,

IF₅

The atomic weights of each element are as;

Iodine = 126.90 g.mol⁻¹

Fluorine = 19.00 g.mol⁻¹

As there are five atoms of Fluorine so, we will multiply the atomic weight of Fluorine by five and that of Iodine by one as there is only one Iodine atom.

Therefore,

Molecular Mass of IF₅ = (1 × 126.90 g.mol⁻¹) + (5 × 19.00 g.mol⁻¹)

Molecular Mass of IF₅ = (126.90 g.mol⁻¹) + (95.00 g.mol⁻¹)

Molecular Mass of IF₅ = 221.90 g.mol⁻¹

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the first three ionization energies of an element x are 590, 1145, and 4912 kj mol-1. what is the most likely formula of the com

joja [24]

<u>Answer:</u> The chemical formula is $XSO_3$

<u>Explanation:</u>

Ionization energy is defined as the amount of energy that is required to remove an electron from a chemical species.

The ionization energy equation for the given values follow:

$X(g)\rightarrow X^+(g)+e^-;E_I=590kJ/mol$

$X^+(g)\rightarrow X^{2+}(g)+e^-;E_I=1145kJ/mol$

$X^{2+}(g)\rightarrow X^{3+}(g)+e^-;E_I=4912kJ/mol$

From the values of ionization energy above, it can be seen that the ionization energy increases as every succeeding electron is removed.

Second ionization energy is a little higher than the first one but there is a huge amount of difference between the third and second ionization energy.

This implies that the ion formed during second ionization energy has a stable configuration and it requires a humongous amount of heat to release the third electron.

Hence, the ion formed will be $X^{2+}$