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3 years ago

Aromatic compounds aliphatic compounds

Chemistry

1 answer:

Nonamiya [84]3 years ago

5 0

Answer:

I hoped it helps you fod blessed:)

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Calculate the number of moles and the mass of the solute in each of the following solutions:(a) 2.00 L of 18.5 M H2SO4, concentr

Vlad [161]

Explanation:

$c=\frac{n}{V}$

c = Concentration of the solution

n = Moles of compound in solution

V = Volume of the solution

a) 2.00 L of 18.5 M of concentrated sulfuric acid.

n= ? c = 18.5 M, V = 2.00 L

$18.5 M=\frac{n}{2.00 L}$

n = 37 moles of sulfuric acid

b) 100.0 mL of $3.8\times 10^{-5} M$ of sodium cyanide

n= ? ,c = $3.8\times 10^{-5} M$ , V = 100.0 mL = 0.1 L

$3.8\times 10^{-5} M=\frac{n}{0.1 L}$

n = $3.8\times 10^{-6} moles$ of sodium cyanide

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n= ? c = 13.3 M, V = 5.50 L

$13.3 M=\frac{n}{5.50 L}$

n = 73.15 moles of formaldehyde.

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n= ? ,c = $1.8\times 10^{-6} M$ , V = 325 mL = 0.325 L

$1.8\times 10^{-6} M=\frac{n}{0.325 L}$

n = $5.85\times 10^{-7} moles$ of iron sulfate.

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