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elixir [45]
2 years ago
15

Give the 7 color harmonies​

Physics
2 answers:
Stolb23 [73]2 years ago
8 0

Answer:

Complementary colors.

Split complementary colors.

Analogous colors.

Triadic harmonies.

Tetradic harmonies.

Monochromatic harmonies.

notsponge [240]2 years ago
7 0

Answer:

Complementary colors.

Split complementary colors.

Analogous colors.

Triadic harmonies.

Tetradic harmonies.

Monochromatic harmonies.

Explanation:

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Medicine A is an effective treatment for the common cold a study was conducted to test the effectiveness of medicine A which que
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According to my research I found questions with the same info with option choices and they are:

A.) How many people in the study had the flu?
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Among those options the answer would be the second choice B)
8 0
3 years ago
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Please help!!
HACTEHA [7]

Answer:

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7 0
3 years ago
A transverse standing wave is set up on a string that is held fixed at both ends. The amplitude of the standing wave at an antin
ZanzabumX [31]

Answer:

a) the maximum transverse speed of a point on the string at an antinode is 5.9899 m/s

b) the maximum transverse speed of a point on the string at x = 0.075 m is 4.2338 m/s

Explanation:

Given the data in the question;

as the equation of standing wave on a string is fixed at both ends

y = 2AsinKx cosωt

but k = 2π/λ and ω = 2πf

λ = 4 × 0.150 = 0.6 m

and f =  v/λ = 260 / 0.6 = 433.33 Hz

ω = 2πf = 2π × 433.33 = 2722.69

given that A = 2.20 mm = 2.2×10⁻³

so V_{max1} = A × ω

V_{max1} = 2.2×10⁻³ × 2722.69 m/s

V_{max1} =  5.9899 m/s

therefore, the maximum transverse speed of a point on the string at an antinode is 5.9899 m/s

b)

A' = 2AsinKx

= 2.20sin( 2π/0.6 ( 0.075) rad )

= 2.20 sin(  0.7853 rad ) mm

= 2.20 × 0.706825 mm

A' = 1.555 mm = 1.555×10⁻³

so

V_{max2} = A' × ω

V_{max2} = 1.555×10⁻³ × 2722.69

V_{max2} = 4.2338 m/s

Therefore, the maximum transverse speed of a point on the string at x = 0.075 m is 4.2338 m/s

8 0
2 years ago
A soccer player heads the ball and sends it flying vertically upwards at a speed of 18.0 m/s . How high above the players ' head
Irina-Kira [14]

Answer:

16.53 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 18.0 m/s.

Final velocity (v) = 0 m/s

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Maximum height (h) =.?

The maximum height reached by the ball can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = 18² – (2 × 9.8 × h)

0 = 324 – 19.6h

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19.6h = 324

Divide both side by 19.6

h = 324 / 19.6

h = 16.53 m

Therefore, the maximum height reached by the ball is 16.53 m

6 0
2 years ago
PLEASE HELP.. ILL GIVE U BRAINLY Do you think that air is made of particles? What evidence do you have to support your claim?
3241004551 [841]

Answer:

yes

Explanation:

I think that air is made of particales because air is made out of gas but it has some particales in the air called aerosols.

7 0
3 years ago
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