In proof testing of circuit boards, the probability that any particular diode will fail is 0.01. Suppose a circuit board contain
1 answer:
Answer: 2 diodes
Explanation:
Given : In proof testing of circuit boards, the probability that any particular diode will fail is 0.01.
The number of diodes contained by circuit board = 200
Then , the expected number of diodes to fail is given by :-
Therefore, there are 2 diodes that we will expect to fail.
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Answer:
Impedance, Z = 107 ohms
Explanation:
It is given that,
Resistance, R = 100 ohms
Inductance,
Capacitance,
Frequency, f = 60 Hz
Voltage, V = 120 V
The impedance of the circuit is given by :
...........(1)
Where
is the capacitive reactance,
is the inductive reactance,
So, equation (1) becomes :
Z = 106.26 ohms
or
Z = 107 ohms
So, the impedance of the circuit is 107 ohms. Hence, this is the required solution.