F = 1/T = 20,000 so T = 1/20,000
<span>distance = speed * time </span>
<span>L = 343 T </span>
<span>L = 343/20,000 </span>
<span>L =. 01715 meters or about 1.7 centimeters</span>
Answer:
Explanation:
Potential energy at the top of the slide
PE = mgh = 49(9.8)(3) = 1,440.6 J
Energy converted to work of friction
W = Fd = 35(10) = 350 J
Converted potential that becomes kinetic energy
1440.6 - 350 = 1090.6 J
KE = ½mv²
v = 
v = 
v = 6.671902...
v = 6.7 m/s
Answer:
T = 850 N
Explanation:
given,
mass of billboard worker = 800 N
length of scaffold = 4 m
weight of the scaffold = 500 N
worker is standing at 1 m from one end.
Tension in the rope = ?
To calculate the tension in the string we have to balance the clockwise and counterclockwise moment of the system.
Weight of the worker and the weight of the scaffold will be in clockwise direction where as the tension will be in counterclockwise direction
now,
800 x 3 + 500 x 2 = T x 4
4T = 3400
T = 850 N
hence, tension in the rope is equal to 850 N
Bob gained (80lbs x 14ft) = 1120 ft-lbs of energy.
Fred gained (110lbs x 14ft) = 1540 ft-lbs of energy
Since they both took the same amount of time, Fred's power (rate
of doing work) was greater than Bob's power (rate of doing work).
C2 = a2 + b2
29^2 = a^2 + 20^2
841 = a^2 + 400
441 = a^2
a = 21