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Brilliant_brown [7]
3 years ago
11

Which object has unbalanced forces acting on it

Physics
1 answer:
Basile [38]3 years ago
8 0

Answer:

If you kick a football and it moves from one place to another, it means that unbalanced forces are acting upon it. Ball moves from one place to another after kicking it. This is an example of unbalanced force.

Explanation:

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Lodestone is a naturally magnetized piece of the mineral magnetite
7 0
4 years ago
Gases tend to deviate from the ideal gas law at
IgorLugansk [536]
<h2>Answer: high pressures</h2>

The Ideal Gas equation is:

P.V=n.R.T  

Where:

P is the pressure of the gas

n the number of moles of gas

R=0.0821\frac{L.atm}{mol.K} is the gas constant

T is the absolute temperature of the gas in Kelvin.  

According to this law, molecules in gaseous state do not exert any force among them (attraction or repulsion) and the volume of these molecules is small, therefore negligible in comparison with the volume of the container that contains them.

Now, real gases can behave approximately to an ideal gas, under the conditions described above.

However, when <u>temperature is low</u> these gases deviate from the  ideal gas behavior, because the molecules move slowly, allowing the repulsion or attraction forces to take effect.

The same happens at <u>high pressures</u>, because the volume of molecules is no longer negligible.

5 0
4 years ago
Scientists experimenting with two charged objects of 2.56 x 10-6 C and 3.34 x 10-7 C displayed a repulsion of 2.26 x 10-3 N. How
Pachacha [2.7K]

Answer:

The objects were 1.8m apart.

Explanation:

We will start stating the Coulomb's Law. It says that:

F_e=\frac{Kq_1q_2}{r^{2}}

Where F_e is the electric force between the objects, q_1 and q_2 are the magnitude of the charge of the objects, r is the distance between them and K is the Coulomb's constant (K=8.9*10^{9} \frac{Nm^{2} }{C^{2} } in vacuum). Solving for the distance r we have:

r=\sqrt{\frac{Kq_1q_2}{F_e} }

Plugging the given values into this equation, we obtain:

r=\sqrt{\frac{(8.9*10^{9}\frac{Nm^{2} }{C^{2} })(2.56*10^{-6}C)(3.34*10^{-7}C)}{2.26*10^{-3}N}}=1.8m

In words, the two charged objects were 1.8m apart.

6 0
3 years ago
Read 2 more answers
I need help with this Physics problem. I've been stuck forever:
snow_tiger [21]
<span>Ball A with a mass of 0.500 kg is moving east at a velocity of 0.800 m/s. It strikes ball B, also of mass 0.500 kg, which is stationary. Ball A glances off B at an angle of 40.0° north of its...Two smart cars depart from the same starting location at the same time and travel different routes to the same destination, arriving at the same time. Explain why the cars travelled different...Given electric flux density D=0.3r^2 ar nc/m^2 in free space a. Find the total charge within the sphere r=3 b. Find the total electric flux leaving the sphere r=4</span>
6 0
3 years ago
Una persona tiene 45 años de edad y una masa de 78 kg. ¿Cuántas horas ha vivido? ¿Cuál
Pavel [41]

Answer:

I will answer this in English.

He has 45 years.

a year has 365 days.

a day has 24 hours.

So he has:

45*365*24  hours = 394,200 hours.

His mass is 78 kg,

And we know that 1 slug = 1lbf*ft/s^2

Then, the first step is transform the 78 kg into lbf.

1kg = 2.2 lbf.

then 78kg = 78*2.2 lbf = 171.6lbf.

Now, the weight is m*g, where m is the mass and g is the gravitational acceleration, in this case the gravitational acceleration in ft/s^2 is:

g =  32.2 ft/s^2

Then the weight in slugs is:

W = 32.2ft/s^2*171.6lbf = 5,525.5 slugs

8 0
3 years ago
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